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05 Jul 2020, 10:52
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48%
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The recipe for Bread X requires 4 cups of flour and 1 tbsp of yeast. The recipe for Bread Y requires 3 cups of flour and 2 tbsp of yeast. If a bakery made a number of loaves of Bread X and Bread Y, was the total amount of flour used over 100 cups?
(1) The total number of loaves baked was over 30.
(2) The total amount of yeast used was less than 40 tbsp.
(1) The total number of loaves baked was over 30.
(2) The total amount of yeast used was less than 40 tbsp.
05 Jul 2020, 11:26
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Given Info:
Bread X require 4F & 1Ys
Bread Y require 3F & 2Y
To find:
Is Flour used >100????
S(1) The total number of loaves baked was over 30.
Let's say 31.
if all are Type X then Flour used is 4*31 which is >100 -- Yes
If all are Type Y, then Flour used is 3*31 which is less than 100-- No
Hence Not sufficient
(2) The total amount of yeast used was less than 40 tbsp.
If all are type X then loaves count can maximum be 39 and flour used is less than 39*4, which is >100 -->Yes
If all are type Y, then loaves count is max 39/2 -->19
And hence flour could max be 19*4 which is less than 100.--> No
Not sufficient.
Combined together-->
X + Y > 30
Or
-X - Y < -30
And
X + 2Y < 40
Solving this
Y<10
X>20
If X 21 and Y min 9 because X + Y is over 30.therefore, minimum
Flour needed is 21*4 + 9*3
=84+27 = 111
These two equations can be solved for Y
Posted from my mobile device
Bread X require 4F & 1Ys
Bread Y require 3F & 2Y
To find:
Is Flour used >100????
S(1) The total number of loaves baked was over 30.
Let's say 31.
if all are Type X then Flour used is 4*31 which is >100 -- Yes
If all are Type Y, then Flour used is 3*31 which is less than 100-- No
Hence Not sufficient
(2) The total amount of yeast used was less than 40 tbsp.
If all are type X then loaves count can maximum be 39 and flour used is less than 39*4, which is >100 -->Yes
If all are type Y, then loaves count is max 39/2 -->19
And hence flour could max be 19*4 which is less than 100.--> No
Not sufficient.
Combined together-->
X + Y > 30
Or
-X - Y < -30
And
X + 2Y < 40
Solving this
Y<10
X>20
If X 21 and Y min 9 because X + Y is over 30.therefore, minimum
Flour needed is 21*4 + 9*3
=84+27 = 111
These two equations can be solved for Y
Posted from my mobile device
yashikaaggarwal
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05 Jul 2020, 11:32
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statement 1: no information about yeast used so the bread loaves could be of brand Y, giving away less than 100 cups of flour or Brand X giving away more than 100 cups of flour (Insufficient)
Statement 2: It could be Brand X giving away 39 loaves of bread to the max or Brand Y giving away 19 loaves of bread. (Not sufficient)
Statement 1&2: total no. Of loaves = 30
Yeast unit used is less than 40
If all 30 loaves are of brand Y it will use 60 yeasts unit. Which is out of question.
So some of them are brand X and Other Y.
So, equation will be
X+Y > 30
X+2Y < 40
Let say X+Y = 31
And X+2Y = 39
Y = 8
And X = 23
So brand X flour units = 23*4 = 92
And brand Y flour units= 8*3 = 24
Total = 116
So the total amount of flour used is over 100.
Which will increase with the increase in capacity.
Answer is C
Posted from my mobile device
Statement 2: It could be Brand X giving away 39 loaves of bread to the max or Brand Y giving away 19 loaves of bread. (Not sufficient)
Statement 1&2: total no. Of loaves = 30
Yeast unit used is less than 40
If all 30 loaves are of brand Y it will use 60 yeasts unit. Which is out of question.
So some of them are brand X and Other Y.
So, equation will be
X+Y > 30
X+2Y < 40
Let say X+Y = 31
And X+2Y = 39
Y = 8
And X = 23
So brand X flour units = 23*4 = 92
And brand Y flour units= 8*3 = 24
Total = 116
So the total amount of flour used is over 100.
Which will increase with the increase in capacity.
Answer is C
Posted from my mobile device
