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31 Jul 2003, 17:53
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The rectangular region contains two circles and a semicircle, each with a radius of 7. If is used as an approximation forπ, then the area of the shaded region is approximately ( Note: Shaded region is just the area inside the rectangle not covered by circles)
(A) 105
(B) 210
(C) 380
(D) 385
(E) 405
(A) 105
(B) 210
(C) 380
(D) 385
(E) 405
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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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31 Jul 2003, 20:11
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See the attached picture.
Length of rectangle = 35
Width = 14
Area of rect. = 35*14=490
Area of 1st whole circle = pi*7^2 = 22/7 * 7^2 = 22*7=154
Area of 2nd whole circle = 154
Area of semicircle = 154/2=77
Total area of circles=154+154+77=385
Area of the rest=490-385=105
Length of rectangle = 35
Width = 14
Area of rect. = 35*14=490
Area of 1st whole circle = pi*7^2 = 22/7 * 7^2 = 22*7=154
Area of 2nd whole circle = 154
Area of semicircle = 154/2=77
Total area of circles=154+154+77=385
Area of the rest=490-385=105
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
