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bmwhype2
The rental charge for a car is 34 cents for the 1st 1/4 mile driven and 6 cents for ever 1/5 mile driven over the initial 1/4 mile.

If a guy paid 1.24 in rental charge, how many miles did he drive?

2.50
3.00
3.25
3.75
4.00


Total Rent = Rent for the first 0.25 mile + Rent After 0.25 mile

Rent for the first 0.25 mile = 34 cents
Rent After 0.25 mile = [6 cent/(1/5 mile)]*(x - 0.25) = 30(x-0.25)
Therefore, Total Rent = 35 + 30(x - 0.25)
124 = 34 + 30(x - 0.25)
90 = 30(x - 0.25)
3 = x - 0.25
x = 3 + 0.25 = $3.25
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The rental charge for a car is 34 cents for the first 1/4 mile driven and 6 cents for every 1/5 mile driven over the initial 1/4 mile. If a man paid $1.24 in rental charges, how many miles did he drive?

We know that 100 cents = 1$
Therefore , Total Amount man paid = $1.24 = 124 cents.
for first 1/4 mile = 34 cents = 124-34 = 90 cents
1/5 of a mile = 6 cents = 15 mile.
total miles drive = 15 mile + 0.25 mile = 15.25 miles
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The rental charge for a car is 34 cents for the first 1/4 mile driven and 6 cents for every 1/5 mile driven over the initial 1/4 mile. If a man paid $1.24 in rental charges, how many miles did he drive?

Let n be the total miles driven.

total amount = rental charge for 1/4 mile initially + rental charge as 6 cents per 1/5 mile

124 = 34 + (n-1/4) * 30 ( 6cents for 1/5 miles => 30 cents/mile...distance chargeable at this rate = n-1/4

=> n = 3+ 1/4 = 3.25 miles
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bmwhype2
The rental charge for a car is 34 cents for the first 1/4 mile driven and 6 cents for every 1/5 mile driven over the initial 1/4 mile. If a man paid $1.24 in rental charges, how many miles did he drive?

A. 2.50
B. 3.00
C. 3.25
D. 3.75
E. 4.00

M22-05

We can let T = the total number of miles driven and create the following equation:

1.24 = 0.34 + 0.06 * (T - 1/4)/(1/5)

0.9 = 0.06 * (T - 1/4) * 5

0.9 = 0.3(T - 1/4)

3 = T - 1/4

T = 3 + 1/4 = 3.25

Answer: C
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The rental charge for a car is 34 cents for the first \(\frac{1}{4}\) mile driven and then 6 cents for each additional \(\frac{1}{5}\) mile driven beyond the initial \(\frac{1}{4}\) mile. If a man paid $1.24 for rental charges, how many miles did he drive?

A. 2.50
B. 3.00
C. 3.25
D. 3.75
E. 4.00


To determine the additional miles driven beyond the first quarter-mile, we first subtract the charge for the initial \(\frac{1}{4}\) mile ($0.34) from the total charge ($1.24), which gives $0.90.

Dividing this by the rate of $0.06 for each \(\frac{1}{5}\) mile segment, we find the driver traveled 15 segments of \(\frac{1}{5}\) mile, or \(15*\frac{1}{5}=3\) miles. Including the initial \(\frac{1}{4}\) mile, the overall distance driven is 3.25 miles.


Answer: C
­i dont know but this is super confusing. Let x be total miles after 1/4 mile driven it would 3/4 miles left right ?

Why are we substracting x- 1/4 to get remaining miles ?

Bunuel And KarishmaB
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Bunuel
The rental charge for a car is 34 cents for the first \(\frac{1}{4}\) mile driven and then 6 cents for each additional \(\frac{1}{5}\) mile driven beyond the initial \(\frac{1}{4}\) mile. If a man paid $1.24 for rental charges, how many miles did he drive?

A. 2.50
B. 3.00
C. 3.25
D. 3.75
E. 4.00


To determine the additional miles driven beyond the first quarter-mile, we first subtract the charge for the initial \(\frac{1}{4}\) mile ($0.34) from the total charge ($1.24), which gives $0.90.

Dividing this by the rate of $0.06 for each \(\frac{1}{5}\) mile segment, we find the driver traveled 15 segments of \(\frac{1}{5}\) mile, or \(15*\frac{1}{5}=3\) miles. Including the initial \(\frac{1}{4}\) mile, the overall distance driven is 3.25 miles.


Answer: C
­i dont know but this is super confusing. Let x be total miles after 1/4 mile driven it would 3/4 miles left right ?

Why are we substracting x- 1/4 to get remaining miles ?

Bunuel And KarishmaB
­
You don't quite get the setup. Let's break it down with an example. Suppose 10.25 miles were driven. For the first 0.25 miles, 34 cents will be paid. For the remaining 10 miles, 6 cents will be paid for each additional 0.2 miles. 10 miles consist of 10/0.2 = 50 segments of 0.2 miles. At 6 cents per segment, the cost for these 10 miles is 50*6 = 300 cents. Therefore, the total rental charge for driving 10.25 miles would be 34 + 300 = 334 cents.­

Hope it's clear.
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