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Bunuel
The roll numbers of students in a college are alpha-numeric sequences of 6 characters. The first and fourth characters are letters while the other four are non-zero digits. While the first character is a vowel, the fourth is a letter from a to e (both inclusive). The second character is 2 and the third is a multiple of 2. The sixth character is 5 more than the fifth. How many roll numbers can be formed?

A. 200
B. 240
C. 300
D. 360
E. 400

There are 5 options (a, e, i, o , u) for the first character

There is 1 option (2) for the second

There are 4 options (2,4,6,8) for the third

There are 5 options (a, b, c, d, e) for the fourth

There are 4 options for the fifth (1, 2, 3, and 4)

There is only 1 option for the sixth (It must be exactly 5 more than the fifth character)

Thus, the total number of options is 5 x 1 x 4 x 5 x 4 x 1 = 20 x 20 = 400

Answer: E
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Archit3110
given its a 6 character alpha numeric sequence
so
first = a,e,i,o,u ; 5
2nd = 2; 1
3rd=2,4,6,8 ; 4
4th = a,b,c,d,e; 5
5th & 6th has to be non zero ; 16,27,38,49 ; 4 possible

total cases possible ; 5*1*4*5*4 ; 400 IMO E


Bunuel
The roll numbers of students in a college are alpha-numeric sequences of 6 characters. The first and fourth characters are letters while the other four are non-zero digits. While the first character is a vowel, the fourth is a letter from a to e (both inclusive). The second character is 2 and the third is a multiple of 2. The sixth character is 5 more than the fifth. How many roll numbers can be formed?

A. 200
B. 240
C. 300
D. 360
E. 400

Hello Archit3110!

How do we find the red numbers?

Kind regards!
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