|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
13 Sep 2019, 11:16
Kudos
Bookmarks
The set of prime factors of 84: 2,3,7
The set of prime factors of integer y has one more element than the set of prime factors of 84: 2,3,7,P (Let the extra prime factor in y be P)
The least possible value of y: P has to be the lowest possible prime factor other than 2,3,7. So P has to be 5. Thus, y= 2*3*5*7= 210
Answer: B
The set of prime factors of integer y has one more element than the set of prime factors of 84: 2,3,7,P (Let the extra prime factor in y be P)
The least possible value of y: P has to be the lowest possible prime factor other than 2,3,7. So P has to be 5. Thus, y= 2*3*5*7= 210
Answer: B
14 Sep 2019, 03:08
Kudos
Bookmarks
Bunuel
A set is considered to have distinct elements.
84 = 2^2 * 3* 7
Set of prime factors of 84 = {2, 3, 7}
Set of prime factors of y will have 4 distinct prime factors. For smallest value of y, the 4 distinct prime factors will be smallest - 2, 3, 5, 7
y = 2*3*5*7 = 210
Answer (B)
05 Apr 2021, 21:08
Kudos
Bookmarks
84 = (2)^2 * 3 * 7
Has 3 unique prime Factors
We need to create the smallest number that has 4 unique prime factors
multiply the 4 smallest prime factors
2 * 3 * 5 * 7 = 210
Posted from my mobile device
Has 3 unique prime Factors
We need to create the smallest number that has 4 unique prime factors
multiply the 4 smallest prime factors
2 * 3 * 5 * 7 = 210
Posted from my mobile device
