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The size of a television screen is given as the length of

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The size of a television screen is given as the length of [#permalink]

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New post 29 Sep 2008, 22:15
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The size of a television screen is given as the length of the screen’s diagonal. If the screens were flat, then
the area of a square 21-inch screen would be how many square inches greater than the area of a square
19-inch screen?

(A) 2
(B) 4
(C) 16
(D) 38
(E) 40
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Re: PS: Television Sets [#permalink]

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New post 29 Sep 2008, 22:32
E. 40

If diagonal of square is 21 (or 19) then side will be 21/sqrt2 (or 19/sqrt2).

Now, difference in area = (21/sqrt2)*(21/sqrt2) - (19/sqrt2)*(19/sqrt2)
= (21^2 - 19^2)/2 = (21-19)(21+19)/2 = (21+19) = 40.

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Re: PS: Television Sets [#permalink]

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New post 30 Sep 2008, 04:28
scthakur wrote:
E. 40

If diagonal of square is 21 (or 19) then side will be 21/sqrt2 (or 19/sqrt2).

Now, difference in area = (21/sqrt2)*(21/sqrt2) - (19/sqrt2)*(19/sqrt2)
= (21^2 - 19^2)/2 = (21-19)(21+19)/2 = (21+19) = 40.


I did the same thing, only i ended up putting 21+19=30!!! and i was thinking i got the approach wrong :) :)

Thanks
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"You have to find it. No one else can find it for you." - Bjorn Borg

Kudos [?]: 709 [0], given: 1

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Kudos [?]: 279 [0], given: 0

Re: PS: Television Sets [#permalink]

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New post 30 Sep 2008, 10:34
amitdgr wrote:
I did the same thing, only i ended up putting 21+19=30!!! and i was thinking i got the approach wrong :) :)

Thanks


No different here. I have already shown an example in a different post :cry:

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Re: PS: Television Sets   [#permalink] 30 Sep 2008, 10:34
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