General expected journey of the train:- Speed = 120 miles/hour = 2 miles/min.
- Time taken = Time lapsed from (5:40 AM to 9:00 AM) = 3 hours 20 min = 200 min.
- Hence, distance covered by the train = 200 / (1/2) = 400 miles.
Journey - First Half:- Speed = 2 miles/min.
- Distance = 200 miles (halfway point).
- Hence, time taken = 200/2 = 100 minutes
- Time at which the train reached the halfway point = 100 minutes from 5:40 AM =
7:20 AM.
Journey - Second Half:- Distance = 200 miles.
- Speed -> varied from 30 miles/hour to 80 miles/hour. i.e. between 1/2 miles/min to 4/3 miles/min.
- If the entire 200-mile distance was covered at 1/2 miles/min, then, the time taken would have been 200 / (1/2) = 400 min.
- If the entire 200-mile distance was covered at 4/3 miles/min, then, the time taken would have been 200 / (4/3) = 150 min.
In reality, the speed varied between these points.
The actual average speed would be something greater than 1/2 miles/min and something lesser than 4/3 miles/min.So,
The actual time taken for the second half of the journey would be between 150 min and 400 min.
150 min < time taken for second half < 400 min. So, by when would the train arrive at Peterson Station?>150 min from 7:20 AM and <400 min from 7:20 AM.
i.e.,
9:50 AM < arrival time < 14:00 PMBernie waited at least 40 min after arrival, before getting on the subway.So,
- Bernie could have got on a subway after 10:30 AM. The first possible subway taken is 10:45 AM.
- Bernie reached the station max by 13:59:59 PM. So, 40 min from this point is 14:39:59 PM. So, the first possible subway taken in this case is 14:45 PM.
How many different times could her subway have departed?10:45, 11:00,.....14:45 -> 17.
Choice E.
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Harsha