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04 Jul 2022, 11:45
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A
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Difficulty:
65%
(hard)
Question Stats:
65% (02:25) correct
35%
(02:36)
wrong
based on 274
sessions
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The sum of five consecutive even numbers of sequence A is 220. What is the sum of a different sequence of five consecutive numbers whose second lowest number in 37 less than double of the lowest number of sequence A?
(A) 220
(B) 221
(C) 223
(D) 225
(E) 235
(A) 220
(B) 221
(C) 223
(D) 225
(E) 235
04 Jul 2022, 12:49
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Sequence A would be X-4, X-2, X, X+2, X+4 x is the median and the average of the 5 numbers with the sum equal to 220. X = 44
second lowest in a group of 5 (y-2,y-1,y,y+1,y+2) --> Y-1 = 2(x-4)-37 = 43.
y=x and median in an arithmetic sequence of the same number of elements.
sum would also equal 220. 42,43,44,45,46
second lowest in a group of 5 (y-2,y-1,y,y+1,y+2) --> Y-1 = 2(x-4)-37 = 43.
y=x and median in an arithmetic sequence of the same number of elements.
sum would also equal 220. 42,43,44,45,46
04 Jul 2022, 16:12
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Bunuel
MedianA = MeanA = 44.
Lowest in A is 40.
Double the lowest in A is 80.
Second-lowest in B is 80-37 = 43.
B is 42, 43, 44, 45, 46.
Last digit is a 0.
Answer choice A.
