Oct 19 07:00 AM PDT  09:00 AM PDT Does GMAT RC seem like an uphill battle? eGMAT is conducting a free webinar to help you learn reading strategies that can enable you to solve 700+ level RC questions with at least 90% accuracy in less than 10 days. Sat., Oct 19th at 7 am PDT Oct 18 08:00 AM PDT  09:00 AM PDT Learn an intuitive, systematic approach that will maximize your success on Fillintheblank GMAT CR Questions. Oct 20 07:00 AM PDT  09:00 AM PDT Get personalized insights on how to achieve your Target Quant Score. Oct 22 08:00 PM PDT  09:00 PM PDT On Demand for $79. For a score of 4951 (from current actual score of 40+) AllInOne Standard & 700+ Level Questions (150 questions) Oct 23 08:00 AM PDT  09:00 AM PDT Join an exclusive interview with the people behind the test. If you're taking the GMAT, this is a webinar you cannot afford to miss!
Author 
Message 
TAGS:

Hide Tags

Senior Manager
Status: Finally Done. Admitted in Kellogg for 2015 intake
Joined: 25 Jun 2011
Posts: 442
Location: United Kingdom
Concentration: International Business, Strategy
GPA: 2.9
WE: Information Technology (Consulting)

The sum of k consecutive integers is 41. If the least integer is 40
[#permalink]
Show Tags
Updated on: 07 Feb 2019, 00:40
Question Stats:
65% (01:32) correct 35% (01:34) wrong based on 205 sessions
HideShow timer Statistics
The sum of k consecutive integers is 41. If the least integer is 40, then k = A. 40 B. 41 C. 80 D. 81 E. 82 I have tried solving this problem by using formula sum of k consecutive integers = k(k+1)/2
Sum = 41 But I am struggling to understand what role does the least integer play over here/. Can you please help?
Official Answer and Stats are available only to registered users. Register/ Login.
_________________
Best Regards, E.
MGMAT 1 > 530 MGMAT 2> 640 MGMAT 3 > 610 GMAT ==> 730
Originally posted by enigma123 on 11 Mar 2014, 03:20.
Last edited by Bunuel on 07 Feb 2019, 00:40, edited 2 times in total.
Renamed the topic and edited the question.




Math Expert
Joined: 02 Sep 2009
Posts: 58453

Re: The sum of k consecutive integers is 41. If the least integer is 40
[#permalink]
Show Tags
11 Mar 2014, 03:45
enigma123 wrote: The sum of k consecutive integers is 41. If the least integer is 40, then k =
A. 40 B. 41 C. 80 D. 81 E. 82
I have tried solving this problem by using formula sum of k consecutive integers = k(k+1)/2
Sum = 41 But I am struggling to understand what role does the least integer play over here/. Can you please help? The sum of k consecutive integers is 41 and the least integer is 40. So, we have the following sum: (40) + (39) + ... = 41. The sum to be positive you must have positive numbers in the sequence as well. Each positive number and its mirror negative number will give the sum of 0, for example, 1+1=0, 2+2=0, 3+3=0, 40+40=0. Since the sum is 41, then the greatest number must be 41: (40) + (39) + ... + (1) + 0 + 1 + ... + 39 + 40 + 41 = 41 (the sum of red part is 0 + 41 = 41). How many terms do we have? 40 negative numbers, 0 and 41 positive numbers, so total of 82. Answer: E.
_________________




Senior Manager
Joined: 06 Aug 2011
Posts: 318

Re: The sum of k consecutive integers is 41. If the least integer is 40
[#permalink]
Show Tags
11 Mar 2014, 07:13
enigma123 wrote: The sum of k consecutive integers is 41. If the least integer is 40, then k =
A. 40 B. 41 C. 80 D. 81 E. 82
I have tried solving this problem by using formula sum of k consecutive integers = k(k+1)/2
Sum = 41 But I am struggling to understand what role does the least integer play over here/. Can you please help? I think bunuel has explain it very nice ! 40........0.........41......total 82 integers.. 40 to 140+1(0)+41(1 to 41)=82 ...
_________________
Bole So Nehal.. Sat Siri Akal.. Waheguru ji help me to get 700+ score !



Intern
Joined: 09 Oct 2011
Posts: 21

Re: The sum of k consecutive integers is 41. If the least integer is 40
[#permalink]
Show Tags
27 Jul 2015, 10:47
The sum of k consecutive integers is 41. If the least integer is 40, then k =
A. 40 B. 41 C. 80 D. 81 E. 82
Consecutive Integers The difference is consistent with each integers , therefore the series can be A.P .
Sum of A.P. = A + (N1 ) D
A= First term D= Difference between each integer N=number of terms
Sum = A + (N  1 ) D 41= 40 + N 1 82 = N
CONSIDER N=K
Answer = E



Intern
Joined: 06 May 2015
Posts: 22

Re: The sum of k consecutive integers is 41. If the least integer is 40
[#permalink]
Show Tags
07 Jul 2016, 22:10
Hello. we can use direct formula = Sn =n/2(2a+(n1)d here sn =41, n =?( we have to find) a=40 & d=1
after applying given value, we will get n=82 so correct answer sis E



Current Student
Status: DONE!
Joined: 05 Sep 2016
Posts: 357

Re: The sum of k consecutive integers is 41. If the least integer is 40
[#permalink]
Show Tags
27 Oct 2016, 14:02
This is another good problem where it is helpful to visualize the number line:
We have 40 off in space on the left hand side of the line and we don't know how far out it goes on the right, but we do know that the sum is a positive number and its 41. Right away, you should think to yourself "okay, if I go out to 40 on the right hand side of the number line, everything on the left hand side will cancel it out." Therefore, if we add one more number, 41, on the right hand side we arrive at our value of 41 for the sum & the number of values on the line altogether is 41+40+1 = 82



Director
Joined: 31 Jul 2017
Posts: 512
Location: Malaysia
GPA: 3.95
WE: Consulting (Energy and Utilities)

Re: The sum of k consecutive integers is 41. If the least integer is 40
[#permalink]
Show Tags
22 Jan 2018, 20:32
enigma123 wrote: The sum of k consecutive integers is 41. If the least integer is 40, then k =
A. 40 B. 41 C. 80 D. 81 E. 82
I have tried solving this problem by using formula sum of k consecutive integers = k(k+1)/2
Sum = 41 But I am struggling to understand what role does the least integer play over here/. Can you please help? The Sum of an AP Series is \((n/2)[2a+(n1)d]\).. Given that \(d = 1\) & \(Sum = 41\), \(a = 40\) Solving above we get, \(n(n81) = 82\).. No need to solve further.. n = 82
_________________
If my Post helps you in Gaining Knowledge, Help me with KUDOS.. !!



Board of Directors
Status: QA & VA Forum Moderator
Joined: 11 Jun 2011
Posts: 4772
Location: India
GPA: 3.5
WE: Business Development (Commercial Banking)

Re: The sum of k consecutive integers is 41. If the least integer is 40
[#permalink]
Show Tags
23 Jan 2018, 00:52
enigma123 wrote: The sum of k consecutive integers is 41. If the least integer is 40, then k =
A. 40 B. 41 C. 80 D. 81 E. 82
I have tried solving this problem by using formula sum of k consecutive integers = k(k+1)/2
Sum = 41 But I am struggling to understand what role does the least integer play over here/. Can you please help? (40 , 39 , 38.............3 , 2 ,  1 , 0 , 1 , 2 , 3 ..............38 , 39 , 40 ) 41 The result of the highlighted part will be 0 , and we have 81 Numbers in this range (40 to 40 including 0) So, The answer will be (E) 82
_________________



Target Test Prep Representative
Status: Head GMAT Instructor
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2815

Re: The sum of k consecutive integers is 41. If the least integer is 40
[#permalink]
Show Tags
24 Jan 2018, 10:37
enigma123 wrote: The sum of k consecutive integers is 41. If the least integer is 40, then k =
A. 40 B. 41 C. 80 D. 81 E. 82 If the least (or first) integer is 40, we see that the sum of the consecutive integers from 40 to 40 will all cancel to zero, and if we include 41 as the final integer in the set, then the sum will be 41. Thus, there are 41  (40) + 1 = 82 integers in total. Answer: E
_________________
5star rated online GMAT quant self study course See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews
If you find one of my posts helpful, please take a moment to click on the "Kudos" button.



NonHuman User
Joined: 09 Sep 2013
Posts: 13259

Re: The sum of k consecutive integers is 41. If the least integer is 40
[#permalink]
Show Tags
06 Mar 2019, 08:24
Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up  doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________




Re: The sum of k consecutive integers is 41. If the least integer is 40
[#permalink]
06 Mar 2019, 08:24






