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# The sum S of the first n consecutive positive even integers is given

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Math Expert
Joined: 02 Sep 2009
Posts: 60633
The sum S of the first n consecutive positive even integers is given  [#permalink]

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30 Jul 2018, 00:01
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5% (low)

Question Stats:

96% (00:46) correct 4% (01:06) wrong based on 696 sessions

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The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

A. 10
B. 11
C. 12
D. 13
E. 14

NEW question from GMAT® Quantitative Review 2019

(PS02978)

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Joined: 10 Aug 2009
Posts: 62
Re: The sum S of the first n consecutive positive even integers is given  [#permalink]

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30 Jul 2018, 00:02
10*11 = 110 so answer is A. No need to solve quadratic as options are very simple to test.

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Retaking gmat for second time, any re-takers please feel free to connect.
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Re: The sum S of the first n consecutive positive even integers is given  [#permalink]

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30 Jul 2018, 00:05
1
1
Bunuel wrote:
The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

A. 10
B. 11
C. 12
D. 13
E. 14

NEW question from GMAT® Quantitative Review 2019

(PS02978)

OA:A

Given n(n + 1)=110, find n.
Plugging in the options
first option,n=10
L.H.S= 10*11=110
R.H.S= 110
L.H.S=R.H.S
hence n =10
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Re: The sum S of the first n consecutive positive even integers is given  [#permalink]

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06 Aug 2018, 07:22
Bunuel wrote:
The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

A. 10
B. 11
C. 12
D. 13
E. 14

NEW question from GMAT® Quantitative Review 2019

(PS02978)

Formula = n(n+1)

as per the question,

n(n+1) = 110

Back solve it. Only option A matches .

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Re: The sum S of the first n consecutive positive even integers is given  [#permalink]

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06 Aug 2018, 08:01
Bunuel wrote:
The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

A. 10
B. 11
C. 12
D. 13
E. 14

NEW question from GMAT® Quantitative Review 2019

(PS02978)

$$n(n + 1) = 10*11$$

Thus, n = 10 Answer must be (A)
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GMAT 1: 500 Q47 V15
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Re: The sum S of the first n consecutive positive even integers is given  [#permalink]

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07 Aug 2018, 01:57
Bunuel wrote:
The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

A. 10
B. 11
C. 12
D. 13
E. 14

NEW question from GMAT® Quantitative Review 2019

(PS02978)

Try plug-in.

A)
if $$n=10$$ , then $$S = n(n+1) = 10 * 11 =110$$.

Ans is A.
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Joined: 03 Jun 2019
Posts: 1942
Location: India
GMAT 1: 690 Q50 V34
Re: The sum S of the first n consecutive positive even integers is given  [#permalink]

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16 Sep 2019, 09:07
Bunuel wrote:
The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

A. 10
B. 11
C. 12
D. 13
E. 14

NEW question from GMAT® Quantitative Review 2019

(PS02978)

The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

S = n(n + 1) = 11*10 = 10*(10+1)
n=10

IMO A
Re: The sum S of the first n consecutive positive even integers is given   [#permalink] 16 Sep 2019, 09:07
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