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The sum S of the first n consecutive positive even integers is given

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The sum S of the first n consecutive positive even integers is given  [#permalink]

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New post 30 Jul 2018, 00:01
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The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

A. 10
B. 11
C. 12
D. 13
E. 14


NEW question from GMAT® Quantitative Review 2019


(PS02978)
Spoiler: OA

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Re: The sum S of the first n consecutive positive even integers is given  [#permalink]

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New post 30 Jul 2018, 00:02
10*11 = 110 so answer is A. No need to solve quadratic as options are very simple to test.


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Re: The sum S of the first n consecutive positive even integers is given  [#permalink]

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New post 30 Jul 2018, 00:05
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Bunuel wrote:
The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

A. 10
B. 11
C. 12
D. 13
E. 14


NEW question from GMAT® Quantitative Review 2019


(PS02978)


OA:A

Given n(n + 1)=110, find n.
Plugging in the options
first option,n=10
L.H.S= 10*11=110
R.H.S= 110
L.H.S=R.H.S
hence n =10
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Re: The sum S of the first n consecutive positive even integers is given  [#permalink]

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New post 06 Aug 2018, 07:22
Bunuel wrote:
The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

A. 10
B. 11
C. 12
D. 13
E. 14


NEW question from GMAT® Quantitative Review 2019


(PS02978)



Formula = n(n+1)

as per the question,

n(n+1) = 110

Back solve it. Only option A matches .

The best answer is A.
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Re: The sum S of the first n consecutive positive even integers is given  [#permalink]

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New post 06 Aug 2018, 08:01
Bunuel wrote:
The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

A. 10
B. 11
C. 12
D. 13
E. 14


NEW question from GMAT® Quantitative Review 2019


(PS02978)

\(n(n + 1) = 10*11\)

Thus, n = 10 Answer must be (A)
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Re: The sum S of the first n consecutive positive even integers is given  [#permalink]

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New post 07 Aug 2018, 01:57
Bunuel wrote:
The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

A. 10
B. 11
C. 12
D. 13
E. 14


NEW question from GMAT® Quantitative Review 2019


(PS02978)


Try plug-in.

A)
if \(n=10\) , then \(S = n(n+1) = 10 * 11 =110\).

Ans is A.
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Re: The sum S of the first n consecutive positive even integers is given  [#permalink]

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New post 16 Sep 2019, 09:07
Bunuel wrote:
The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

A. 10
B. 11
C. 12
D. 13
E. 14


NEW question from GMAT® Quantitative Review 2019


(PS02978)


The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

S = n(n + 1) = 11*10 = 10*(10+1)
n=10

IMO A
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Re: The sum S of the first n consecutive positive even integers is given   [#permalink] 16 Sep 2019, 09:07
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