The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?

A. 10
B. 11
C. 12
D. 13
E. 14

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(PS02978)
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OA:A

Given n(n + 1)=110, find n.
Plugging in the options
first option,n=10
L.H.S= 10*11=110
R.H.S= 110
L.H.S=R.H.S
hence n =10

\(n(n + 1) = 10*11\)

Thus, n = 10 Answer must be (A)
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