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30 Jul 2018, 00:01
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
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Question Stats:
96% (00:48) correct
4%
(01:17)
wrong
based on 2227
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The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?
A. 10
B. 11
C. 12
D. 13
E. 14
(PS02978)
A. 10
B. 11
C. 12
D. 13
E. 14
(PS02978)
30 Jul 2018, 00:02
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10*11 = 110 so answer is A. No need to solve quadratic as options are very simple to test.
Sent from my iPhone using GMAT Club Forum
Sent from my iPhone using GMAT Club Forum
30 Jul 2018, 00:05
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Bunuel
The sum S of the first n consecutive positive even integers is given by S = n(n + 1). For what value of n is this sum equal to 110 ?
A. 10
B. 11
C. 12
D. 13
E. 14
(PS02978)
A. 10
B. 11
C. 12
D. 13
E. 14
NEW question from GMAT® Quantitative Review 2019
(PS02978)
OA:A
Given n(n + 1)=110, find n.
Plugging in the options
first option,n=10
L.H.S= 10*11=110
R.H.S= 110
L.H.S=R.H.S
hence n =10
