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# The table above shows the number of students in three clubs at McAulif

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The table above shows the number of students in three clubs at McAulif  [#permalink]

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21 Feb 2018, 02:10
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Difficulty:

15% (low)

Question Stats:

82% (01:57) correct 18% (02:28) wrong based on 85 sessions

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The table above shows the number of students in three clubs at McAuliffe School. Although no student is in all three clubs, 10 students are in both chess and drama, 5 students are in both chess and math, and 6 students are in both drama and math. How many different students are in the three clubs?

(A) 68
(B) 69
(C) 74
(D) 79
(E) 84

Attachment:

Capture.PNG [ 5.21 KiB | Viewed 4267 times ]

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Re: The table above shows the number of students in three clubs at McAulif  [#permalink]

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21 Feb 2018, 03:16
broall wrote:
Attachment:
Capture.PNG

The table above shows the number of students in three clubs at McAuliffe School. Although no student is in all three clubs, 10 students are in both chess and drama, 5 students are in both chess and math, and 6 students are in both drama and math. How many different students are in the three clubs?

(A) 68
(B) 69
(C) 74
(D) 79
(E) 84

10 c and d
5 c and m
6 d and m

total = only one + 2(only two) + 3 ( all three)

40+30+25 = only one + 2(10+5+6) + 3(0)

only one = 53

now only one club = 53

different students = 53+10+5+6+0 = 74

(C) imo
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Re: The table above shows the number of students in three clubs at McAulif  [#permalink]

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21 Feb 2018, 20:20
broall wrote:
Attachment:
The attachment Capture.PNG is no longer available

The table above shows the number of students in three clubs at McAuliffe School. Although no student is in all three clubs, 10 students are in both chess and drama, 5 students are in both chess and math, and 6 students are in both drama and math. How many different students are in the three clubs?

(A) 68
(B) 69
(C) 74
(D) 79
(E) 84

Attachment:

vennclubs.png [ 11.74 KiB | Viewed 3639 times ]

There are formulas for this sort of problem.
In this case, I prefer a Venn diagram.

We have totals for each club, and the overlap numbers.
Find the students who are in ONLY one club with the Venn diagram.

Draw the diagram, and write in information.
Start with the most restrictive information: there are 0 in all three clubs
Next most restrictive: the number in the intersections (10, 5, 6)
Finally, derive the number of students who are in ONLY one club from CLUB TOTAL - TWO OVERLAPs, for each club

Add all the numbers inside the Venn diagram.
That is the number of different students in the three clubs.

GIVEN (write this info in the diagram)
Chess total = 40
Drama total = 30
Math total = 25
C + D = 10
C + M = 5
D + M = 6
All three = 0

DERIVE how many in ONLY ONE
Total must equal 40
(10 + 5 = 15) (gray regions) of those 40 are in other clubs.
Chess only: (40 - 15) = 25

Total must equal 30.
(10 + 6) = 16 (gray regions) of those 30 are in other clubs.
Drama only: (30 - 16) = 14

Total must equal 25
(5 + 6) = 11 (gray regions) are in other clubs.
Math only: (25 - 11) = 14

Add the numbers in each region:
25 + 14 + 14 + 10 + 6 + 5 = 74

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Re: The table above shows the number of students in three clubs at McAulif  [#permalink]

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15 Mar 2019, 18:48
1
1
broall wrote:

The table above shows the number of students in three clubs at McAuliffe School. Although no student is in all three clubs, 10 students are in both chess and drama, 5 students are in both chess and math, and 6 students are in both drama and math. How many different students are in the three clubs?

(A) 68
(B) 69
(C) 74
(D) 79
(E) 84

Attachment:
Capture.PNG

We can create the equation:

Total = #chess + #drama + #math - #chess and drama - #chess and math - #drama and math + #all three

Total = 40 + 30 + 25 - 10 - 5 - 6 + 0

Total = 74

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Re: The table above shows the number of students in three clubs at McAulif   [#permalink] 15 Mar 2019, 18:48
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