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11 Sep 2007, 11:03
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The total cost of housing projects with F units is 1,750,000. What is the cost per unit of the housing project?
1. If half as many units were built for the same total price,the cost per unit is 250,000
2. If 6 More units were built for the same total price, the total price, the cost per unit would be 3750 Less
OA is D
But here is where I am confused
I can see how A would be correct,
Writing an equation for B
( X - 3750 ) ( f + 6) = 1.75 Million
xf = 1.75 Million
Substituting for F, we get a quadratic equation that can have 2 possible values for f..
When you get a quadratic equation in a DS option, how do you decide?
1. If half as many units were built for the same total price,the cost per unit is 250,000
2. If 6 More units were built for the same total price, the total price, the cost per unit would be 3750 Less
OA is D
But here is where I am confused
I can see how A would be correct,
Writing an equation for B
( X - 3750 ) ( f + 6) = 1.75 Million
xf = 1.75 Million
Substituting for F, we get a quadratic equation that can have 2 possible values for f..
When you get a quadratic equation in a DS option, how do you decide?
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11 Sep 2007, 11:20
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cost per unit = total cost / number of units
cost per unit = 1,750,000 / F
Need to find F
1. If half as many units were built for the same total price,the cost per unit is 250,000
--------------------------------------------------------------------------
1,750,000 / (F/2) = 250,000 --> F = 1,750,000 / 125,000 = # hourses
So,
Cost per unit = 1,750,000 / # ... no need to calculate
statement 1 is sufficient
2. If 6 More units were built for the same total price, the total price, the cost per unit would be 3750 Less
-----------------------------------------------------------------------------
1,750,000 / (F+6) = ( 1,750,000 / F ) - 3,750 . one equation/ one unkown variable ... can find F
statement 2 is sufficient
ANS: D
cost per unit = 1,750,000 / F
Need to find F
1. If half as many units were built for the same total price,the cost per unit is 250,000
--------------------------------------------------------------------------
1,750,000 / (F/2) = 250,000 --> F = 1,750,000 / 125,000 = # hourses
So,
Cost per unit = 1,750,000 / # ... no need to calculate
statement 1 is sufficient
2. If 6 More units were built for the same total price, the total price, the cost per unit would be 3750 Less
-----------------------------------------------------------------------------
1,750,000 / (F+6) = ( 1,750,000 / F ) - 3,750 . one equation/ one unkown variable ... can find F
statement 2 is sufficient
ANS: D
11 Sep 2007, 11:21
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beatgmat
What if one of the two numbers(x) is negative?
