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# The total cost of water for one year in Community Z of

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Joined: 30 Jun 2008
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The total cost of water for one year in Community Z of [#permalink]

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08 Oct 2008, 06:42
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The total cost of water for one year in Community Z of 120,000 homes is \$75,000. If the cost were to increase to \$80,000 for the community, by approximately what percent would the average cost of water for each household in Community Z?

A) 70%
B) 13%
C) 7%
D) 5%
E) 1.3%
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Kudos [?]: 708 [1], given: 1

Manager
Joined: 15 Apr 2008
Posts: 164

Kudos [?]: 12 [1], given: 1

Re: PS: Percentage [#permalink]

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08 Oct 2008, 06:58
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I think the question here is the percentage increase in cost per household.

the answer is C

cost per household before increase=75,000/120,000=.625
cost per household after increase=80,000/120,000=.666

the difference= .666-.625=.041

the percentage increase =.041/.625*100=6.56%

the answer is approx. 7%

Kudos [?]: 12 [1], given: 1

Senior Manager
Joined: 21 Apr 2008
Posts: 487

Kudos [?]: 56 [0], given: 13

Schools: Kellogg, MIT, Michigan, Berkeley, Marshall, Mellon
Re: PS: Percentage [#permalink]

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08 Oct 2008, 08:24
I would say the same:

% increase: (80,000-75,000)/75,000 aprox. 7%

Am I missing something?

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SVP
Joined: 05 Jul 2006
Posts: 1750

Kudos [?]: 430 [0], given: 49

Re: PS: Percentage [#permalink]

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08 Oct 2008, 14:22
amitdgr wrote:
The total cost of water for one year in Community Z of 120,000 homes is \$75,000. If the cost were to increase to \$80,000 for the community, by approximately what percent would the average cost of water for each household in Community Z?

A) 70%
B) 13%
C) 7%
D) 5%
E) 1.3%

75000/120000 = 75/120 = 15/24 = 5/8

80000/120000 = 8/12 = 2/3

2/3 - 5/8 = 16-15/24 = 1/24

% = (1/24)/(5/8) = 1/24*8/5 *100= 6.7% approx = 7%

Kudos [?]: 430 [0], given: 49

Re: PS: Percentage   [#permalink] 08 Oct 2008, 14:22
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# The total cost of water for one year in Community Z of

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