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[GMAT math practice question]

(Number Properties) \(x\) is a positive integer. What is the minimum value of \(x\)?

1) \(f(x)\) denotes the number of positive divisors of \(x\).

2) \(f(420)·f(x) = 96.\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

Since we have \(1\) variable (\(x\)) and \(0\) equations, D is most likely the answer. So, we should consider each condition on its own first.

Let’s look at the condition 1). It tells us just the definition of a function \(f(x)\), therefore not giving us enough information to solve the question.
The answer is not unique, so the condition is not sufficient, according to Common Mistake Type 1, which states that the number of answers must be only one.

Let’s look at the condition 2). It tells us that \(f(420)·f(x) = 96\). Since we do not have a definition of \(f(x)\), the answer is not unique, and condition 2) is not sufficient according to Common Mistake Type 1, which states that the number of answers must be only one.

Both conditions 1) & 2) together tell us that \(x\) has \(4\) factors for the following reason.

Remember the property that if \(n = p^aq^br^c\) where \(p, q\), and \(r\) are different prime numbers, \(n\) has \((a + 1)(b + 1)(c + 1)\) factors.

Since we have \(420 = 2^23^15^17^1\), it has \((2 + 1)(1 + 1)(1 + 1)(1 + 1) = 3·2·2·2 = 24\) factors.

We have \(f(420)·f(x) = 24·f(x) = 96\) or \(f(x) = 4\), which means \(x\) has \(4\) factors.

Then we have two possibilities for \(x\), which are \(x = p^3\) or \(x = p·q\) where \(p\) and \(q\) are different prime numbers.

Then we have \(2^3 = 8\) or \(2·3 = 6\) as the possible values of \(x\).

Therefore, the minimum is \(6\).

The answer is unique, and both conditions 1) and 2) together are sufficient according to Common Mistake Type 2, which states that the number of answers must be only one.

Both conditions 1) & 2) together are sufficient.

Therefore, C is the correct answer.
Answer: C

If the original condition includes “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations,” etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A, B, C, or E.
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How many digits does \(2^{17}*5^{10}\) have?


A. 11
B. 13
C. 15
D. 17
E. 19


Solution:

To find the number of digits, pair up 2 and 5 with common powers, and we get

=> \(2^{17}\) * \(5^{10}\) = \(2^{7}\) * \(2^{10}\) * \(5^{10}\)

=> If we use the exponent property of \(a^x\) * \(b^x\) = \((ab)^x\), we get

=>\(2^{17}\) * \(5^{10}\) = \(2^{7}\) * \(2^{10}\) * \(5^{10}\) = 128 * \(10^{10}\)

=> Since 128 * \(10^{10}\) has 128 as the first 3 digits followed by 10 zeros, the total number of digits of \(2^{17}\) * \(5^{10}\) = 3 + 10 = 13.

Therefore, B is the correct answer.

Answer B
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[GMAT math practice question]

(Algebra) What is the value of \(a + b\)?

1) The equation \(2(x + a) = bx - 4\) has more than one solution.

2) \(a\) and \(b\) have the same absolute value and \(ab < 0\).

=>
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question.
We have to find the value of \(a + b\).

Follow the second and the third step: From the original condition, we have \(2\) variables (\(a\) and \(b\)). To match the number of variables with the number of equations, we need 2 equations. Since conditions (1) and (2) will provide 1 equation each, C would most likely be the answer.

Recall 3 Principles and choose C as the most likely answer.
Let’s look at both conditions together. However, since the value of condition (1) is equal to the value of condition (2), by Tip 1, we get D as the most likely answer. Let’s look at each condition separately.
Condition 1) tells us that \(a = -2\) and \(b = 2\). In order for the equation to have more than one solution, the corresponding coefficients on both sides must be equal, respectively. Then we have the left-hand side \(2(x + a) = 2x + 2a\) and we have \(2x + 2a = bx – 4.\) Since the equation \(2x + 2a = bx – 4\) has more than one solution, we have \(2 = b\) and \(2a = -4.\) Thus, condition 1) tells us that \(a = -2\) and \(b = 2.\)

Then we have \(a + b = -2 + 2 = 0.\)

The answer is unique, so the condition is sufficient according to Common Mistake Type 2, which states that the number of answers must be only one.
Condition 2) tells us that \(a = -b.\) Since we have \(|a| = |b|\) and \(ab < 0, a\) and \(b\) have different signs and \(a = -b\). Thus, we have \(a + b = 0. \)

The answer is unique, so the condition is sufficient according to Common Mistake Type 2, which states that the number of answers must be only one.
Each condition alone is sufficient.
Therefore, D is the correct answer.
Answer: D

Normally, in problems that require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in Common Mistake Types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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[GMAT math practice question]

(Algebra) \(x, y,\) and \(z (x < y < z)\) are positive integers. What is the value of \(x\)?

1) \(x, y,\) and \(z\) are consecutive integers.

2) \(12 + 13 + 14 + 15 = x + y + z.\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

Since we have \(3\) variables (\(x, y,\) and \(z\)) and \(0\) equations, E is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2) together give us that \(y = x + 1, z = x + 2\) and \(12 + 13 + 14 + 15 = x + x + 1 + x + 2\), which is equivalent to \(54 = 3x + 3, 3x = 51\), or \(x = 27.\)

Since \(x, y\), and \(z\) with \(x < y < z\) are consecutive integers, we have \(y = x + 1\) and \(z = x + 2.\)

When we replace \(y\) and \(z\) with \(x + 1\) and \(x + 2\) in the equation \(12 + 13 + 14 + 15 = x + y + z,\) we have \(54 = 3x + 3\) or \(3x = 51.\)
Thus, we have \(x = 17.\)

The answer is unique, and conditions 1) and 2) together are sufficient according to Common Mistake Type 2, which states that the number of answers must be only one.

Therefore, C is the answer.
Answer: C

In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B, or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2) when taken together. Obviously, there may be occasions on which the answer is A, B, C, or D.
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[GMAT math practice question]

(Function) \(f(x)\) is a function. What is the value of \(f(2020)\)?

1) \(f(10)=11\)

2) \(f(x+3)=\frac{f(x) - 1}{f(x) + 1}\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

Since we have many variables to determine a function, E is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)

\(f(13)=\frac{f(10) - 1}{f(10) + 1}=\frac{11 - 1}{11 + 1}=\frac{5}{6}.\)

\(f(16)=\frac{f(13) - 1}{f(13) + 1}=\frac{5}{6} - 1/\frac{5}{6} + 1=\frac{-1}{11}.\)

\(f(19)=\frac{f(16)-1}{f(16)+1}=\frac{-1}{11}-1/\frac{-1}{11}+1=\frac{-6}{5}\)

\(f(22)=\frac{f(16) - 1}{f(16) + 1}=\frac{-6}{5} - 1/\frac{-6}{5} + 1=11.\)

Since we have \(2008 = 4*5002 + 0\) has a remainder \(0\) when it is divided by \(4\),\( f(2008) = f(16) = \frac{-1}{11}.\)
Since both conditions together yield a unique solution, they are sufficient.

Therefore, C is the answer.
Answer: C

In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2) when taken together. Obviously, there may be occasions on which the answer is A, B, C, or D.
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[GMAT math practice question]

(Equation) \(a\) and \(b\) are different integers. What is the root of \((x - a)^2 = (x - b)^2\)?

1) \(a – b = 3\)

2) \(a + b = 7\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary.

The question \((x - a)^2 = (x - b)^2\) is equivalent to \(x = \frac{(a + b)}{2}\) for the following reason.
\((x - a)^2 = (x - b)^2\)

⇔ \((x - a)^2 - (x - b)^2 = 0\)

⇔ \(((x - a) - (x - b)) ((x - a) + (x - b)) = 0\)

⇔ \((-a + b)(2x - (a + b)) = 0\)

⇔ \((2x - (a + b)) = 0\) (by dividing both sides by \(-a + b\) since \(a ≠ b\))

⇔ \(2x = (a + b)\) (by adding (\(a + b\)) to both sides)

⇔ \(x = \frac{(a + b)}{2}\) (by dividing both sides by \(2\))

So, we have to find the value of \(a + b\).

Thus, look at condition (2). It tells us that \(a + b = 7\), which is exactly what we are looking for. The answer is unique, and the condition is sufficient according to Common Mistake Type 2, which states that the number of answers must be only one.
Condition (1) tells us that \(a – b = 3\), from which we cannot determine the unique value of \(a + b. \) The answer is not unique, and the condition is not sufficient according to Common Mistake Type 2, which states that the number of answers must be only one.
Condition (2) ALONE is sufficient.
Therefore, B is the answer.
Answer: B
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[GMAT math practice question]

(Function) \(f(x)\) is a function. What is the value of \(f(2020)\)?

1) \(f(10)=11\)

2) \(f(x+3)=\frac{f(x) - 1}{f(x) + 1}\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

Since we have many variables to determine a function, E is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)

\(f(13)=\frac{f(10) - 1}{f(10) + 1}=\frac{11 - 1}{11 + 1}=\frac{5}{6}.\)

\(f(16)=\frac{f(13) - 1}{f(13) + 1}=\frac{5}{6} - 1/\frac{5}{6} + 1=\frac{-1}{11}.\)

\(f(19)=\frac{f(16)-1}{f(16)+1}=\frac{-1}{11}-1/\frac{-1}{11}+1=\frac{-6}{5}\)

\(f(22)=\frac{f(16) - 1}{f(16) + 1}=\frac{-6}{5} - 1/\frac{-6}{5} + 1=11.\)

Since we have \(2008 = 4*5002 + 0\) has a remainder \(0\) when it is divided by \(4\),\( f(2008) = f(16) = \frac{-1}{11}.\)
Since both conditions together yield a unique solution, they are sufficient.

Therefore, C is the answer.
Answer: C

In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2) when taken together. Obviously, there may be occasions on which the answer is A, B, C, or D.
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[GMAT math practice question]

(Algebra) What is the value of \(a + b\)?

1) The equation \(2(x + a) = bx - 4\) has more than one solution.

2) \(a\) and \(b\) have the same absolute value and \(ab < 0\).

=>
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question.
We have to find the value of \(a + b\).

Follow the second and the third step: From the original condition, we have \(2\) variables (\(a\) and \(b\)). To match the number of variables with the number of equations, we need 2 equations. Since conditions (1) and (2) will provide 1 equation each, C would most likely be the answer.

Recall 3 Principles and choose C as the most likely answer.
Let’s look at both conditions together. However, since the value of condition (1) is equal to the value of condition (2), by Tip 1, we get D as the most likely answer. Let’s look at each condition separately.
Condition 1) tells us that \(a = -2\) and \(b = 2\). In order for the equation to have more than one solution, the corresponding coefficients on both sides must be equal, respectively. Then we have the left-hand side \(2(x + a) = 2x + 2a\) and we have \(2x + 2a = bx – 4.\) Since the equation \(2x + 2a = bx – 4\) has more than one solution, we have \(2 = b\) and \(2a = -4.\) Thus, condition 1) tells us that \(a = -2\) and \(b = 2.\)

Then we have \(a + b = -2 + 2 = 0.\)

The answer is unique, so the condition is sufficient according to Common Mistake Type 2, which states that the number of answers must be only one.
Condition 2) tells us that \(a = -b.\) Since we have \(|a| = |b|\) and \(ab < 0, a\) and \(b\) have different signs and \(a = -b\). Thus, we have \(a + b = 0. \)

The answer is unique, so the condition is sufficient according to Common Mistake Type 2, which states that the number of answers must be only one.
Each condition alone is sufficient.
Therefore, D is the correct answer.
Answer: D

Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in Common Mistake Types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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[GMAT math practice question]

(absolute value) Is \(x<y<z\) ?

\(1) |x+1|<y<z+1\)
\(2) |x-1|<y<z-1\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Since we have \(3\) variables (\(x, y\) and \(z\)) and \(0\) equations, E is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)
By condition 1), \(x < y\) since \(x < x + 1 ≤ | x + 1 | < y\).
By condition 2), \(y < z\) since \(y < z – 1 < z.\)
Therefore, \(x < y < z\).
Thus, both conditions 1) & 2) together are sufficient.

Since this question is an absolute value question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.

Condition 1)
If \(x = 1, y = 3\), and \(z = 5,\) then the answer is ‘yes’.
If \(x = 1, y = 3,\) and \(z = 2.9\), then the answer is ‘no’ since z < y.
Thus, condition 1) is not sufficient, since it does not yield a unique solution.

Condition 2)
If \(x = 1, y = 3,\) and \(z = 5\), then the answer is ‘yes’.
If \(x = 3.1, y = 3,\) and \(z = 5\), then the answer is ‘no’ since \(x > y\).
Thus, condition 2) is not sufficient, since it does not yield a unique solution.

Therefore, C is the answer.
Answer: C

In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B, or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2), when taken together. Obviously, there may be occasions on which the answer is A, B, C, or D.
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[GMAT math practice question]

(algebra) \(x\) and \(y\) are integers. If \(y≠3\), is \(x=4\)?

\(1) x+y=7\)
\(2) x^2+y^2=25\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Since we have \(2\) variables (\(x\) and \(y\)) and \(0\) equations, C is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can
save time by considering conditions 1) & 2) together first.

Conditions 1) & 2):
Since \(y = 7 – x, x^2+y^2=25\) is equivalent to \(x^2+(7-x)^2=25\) or \(2x^2 – 14x + 24 = 0.\)
This factors as \(2(x^2 – 7x + 12) = 0\) or \(2(x-3)(x-4) = 0.\)
So, \(x = 3\) and \(y = 4\), or \(x = 4\) and \(y = 3\).
Since \(y ≠3\), we must have \(x = 3\) and \(x\) can’t be \(4\).
Since ‘no’ is also a unique answer by CMT (Common Mistake Type) 1, both conditions are sufficient, when used together.

Since this question is an integer question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.

Condition 1)
Since \(y = 7 – x ≠ 3, x\) can’t be \(4\). So, we have a unique answer, which is “no”.

Since ‘no’ is also a unique answer by CMT (Common Mistake Type) 1, condition 1) is sufficient.

Condition 2)

If \(x = 4\) and \(y = -3\), then \(x^2+y2 = 25\), and the answer is “yes”.
If \(x = 3\) and \(y = 4,\) then \(x^2+y2 = 25\), and the answer is “no”.
Thus, condition 2) is not sufficient, since it does not yield a unique solution.

Therefore, A is the answer.
Answer: A

Normally, in problems that require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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[GMAT math practice question]

(Statistics) The standard deviation of the salaries of the workers in company \(A\) is \(\sqrt{5}\) and that of the workers in company \(B\) is \(\sqrt{30}.\) What is the standard deviation of the salary of company \(A\) and B’s workers together?

1) The number of workers in company \(A\) is \(20\) and that of company \(B\) is \(30\).
2) The averages of the salaries of the workers in companies \(A\) and \(B\) are the same.

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Since we don’t know how many workers companies A and B have, we have many variables and 0 equations, and E is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)
Let \(m\) be the average of the salaries of \(A\) and \(B.\)

Assume a1, a2, …, a20 are the salaries of the workers in A and b1, b2, …, b30 are those of the workers in B.
Since the standard deviation of the company A is \(\sqrt{5}\), we have
[(a1-m)^2+(a2-m)^2 + … + (a20-m)^2] / 20 = 5 or (a1-m)^2+(a2-m)^2 + … + (a20-m)^2 = 100.
Since the standard deviation of the company B is \(\sqrt{30}\), we have
[(b1-m)^2+(b2-m)^2 + … + (b30-m)^2] / 30 = 30 or (b1-m)^2+(b2-m)^2 + … + (b30-m)^2 = 900.
Then, we have
[(a1-m)^2+(a2-m)^2 + … + (a20-m)^2 + (b1-m)^2+(b2-m)^2 + … + (b30-m)^2] / 50
= (100 + 900) / (20 + 30) = 1000/50 = 20.
The standard deviation of the combined set of A and B is \(\sqrt{20}=2\sqrt{5}.\)

Since both conditions together yield a unique solution, they are sufficient.

Since this question is a statistics question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.

Condition 1)
Since there is no relation between the number of data and the standard deviation, condition 1) is not sufficient.

Condition 2)
Since there is no relation between the average and the standard deviation, condition 2) is not sufficient.

Therefore, C is the answer.
Answer: C

In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2) when taken together. Obviously, there may be occasions on which the answer is A, B, C, or D.
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[GMAT math practice question]

(Number Property) \(a, b,\) and \(c\) are integers. Is \(2(a^4 + b^4 + c^4)\) a perfect square?

1) \(a = 1, b = 1\), and \(c = -2\)

2) \(a + b + c = 0\)

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Condition 1)

Since we have \(a = 1, b = 1,\) and \(c = 2\), we have

\(2(a^4 + b^4 + c^4) = 2(1^4 + 1^4 + 2^4) \)

\(= 2(1 + 1 + 16) \)

\(= 2*18 \)

\(= 36.\)

\(2(a^4 + b^4 + c^4) = 36\) is a perfect square and the answer is ‘yes’.

Since condition 1) yields a unique solution, it is sufficient.

Condition 2)

Since \((a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca), \)

we have \(a^2 + b^2 + c^2 = -2(ab + bc + ca).\)

Then, rearranging the second formula gives us:
\((a^2 + b^2 + c^2)^2 = (-2(ab + bc + ca))^2 \)

\(= 4(ab + bc + ca)(ab + bc + ca)\)

\(= 4(a^2b^2 + ab^2c + a^2bc + ab^2c + b^2c^2 + abc^2 + a^2bc + abc^2 + a^2c^2)\)

\(= 4((a^2b^2 + b^2c^2 + a^2c^2 + 2ab^2c + 2a^2bc + 2abc^2) \)

\(= 4(a^2b^2 + b^2c^2 + c^2a^2 + 2abc(a + b + c))\)

\(= 4(a^2b^2 + b^2c^2 + c^2a^2), \)since \(a + b + c = 0\)

Following the pattern in the first equation gives us:
\((a^2 + b^2 + c^2)^2 = a^4 + b^4 + c^4 + 2(a^2b^2 + b^2c^2 + c^2a^2)\)

We now have two equations:
\( (a^2 + b^2 + c^2)^2 = a^4 + b^4 + c^4 + 2(a^2b^2 +b^2c^2+ c^2a^2)\)

\((a^2 + b^2 + c^2)^2 = 4(a^2b^2 + b^2c^2 + c^2a^2)\)

Combining the two equations gives us:
\(a^4 + b^4 + c^4 + 2(a^2b^2 + b^2c^2+ c^2a^2) = 4(a^2b^2 + b^2c^2 + c^2a^2)\)

\(a^4 + b^4 + c^4 = 2(a^2b^2 + b^2c^2 + c^2a^2)\)

\(2(a^4 + b^4 + c^4) = 4(a^2b^2 + b^2c^2 + c^2a^2) = (a^2 + b^2 + c^2)^2.\)

Thus, \(2(a^4 + b^4 + c^4)\) is a perfect square.

Since condition 2) yields a unique solution, it is sufficient.

Therefore, D is the answer.
Answer: D

This question is a CMT 4(B) question: condition 1) is easy to work with, and condition 2) is difficult to work with. For CMT 4(B) questions, D is most likely the answer.
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[GMAT math practice question]

(Number Properties) Is \(\sqrt{A}\) an irrational number?

1) \(A = (n-1)^2+n^2+(n+1)^2\)

2) \(A\) is an integer, and the units digit of \(A\) is \(2\).

=>

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Since we have \(1\) variable (\(A\)) and \(0\) equations, D is most likely the answer. So, we should consider each condition on its own first.

Condition 1)
\(A = (n-1)^2+n^2+(n+1)^2\)

\(= (n – 1)(n – 1) + n^2 + (n + 1)(n + 1)\)

\(= n^2 – n – n + 1 + n^2 + n^2 + n + n + 1\)

\(= 3n^2 + 2\)

Squares of integers do not have the remainder 2 when it is divided by 3, for the following reason:
Case 1) \(n = 3k\)

\(n^2 = (3k)^2 = 9k^2 = 3(3k^2) + 0\)

Case 2) \(n = 3k+1\)

\(n^2 = (3k+1)^2 = 9k^2 + 9k + 1 = 3(3k^2+3k) + 1\)

Case 3) \(n = 3k+2\)

\(n^2 = (3k+2)^2 = 9k^2 + 12k + 4 = 3(3k^2+4k+1) + 1\)

Thus, A is not a square, A is an irrational number, and the answer is ‘no’.

Since 'no' is also a unique answer, according to CMT (Common Mistake Type) 1, condition 1) is sufficient.

Condition 2)
\(0^2 = 0, 1^2 = 1, 2^2 = 4, 3^2 = 9, 4^2 = 16, 5^2=25, 6^2 = 36, 7^2 = 49, 8^2 = 64, 9^2 = 81.\)

Thus, squares do not have a units digit 2 and the answer is ‘no’.

Since 'no' is also a unique answer, according to CMT (Common Mistake Type) 1, condition 2) is sufficient.

Therefore, D is the answer.
Answer: D

This question is a CMT 4(B) question: condition 2) is easy to work with, and condition 1) is difficult to work with. For CMT 4(B) questions, D is most likely the answer.

If the original condition includes “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations,” etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A, B, C, or E.
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[GMAT math practice question]

(Equation) What is the value of \(4a + 2b\)?

1) \((a - b)^2 - 3(a - b) – 18 = 0\)

2) \(a + b = 8\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
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Since we have \(2\) variables (\(a\) and \(b\)) and \(0\) equations, C is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)
From condition 1) we get:
\((a - b)^2 - 3(a - b) – 18 = 0\)

⇔ Let \(x = (a + b)\) giving us:

⇔ \(x^2 – 3x - 18 = 0\)

⇔ \((x + 3)(x – 6)\) (trinomial factoring)

⇔ \(((a-b) + 3)((a - b) - 6) = 0\) (substituting \((a + b)\) back in)

⇔ \(a - b = -3\) or \(a - b = 6\)

When we consider \(a - b = -3\) from condition 1) and \(a + b = 8\) from condition 2) and add them together we get \(2a = 5\), and \(a = \frac{5}{2}\). Substituting that back into the second equation gives us \(\frac{5}{2} + b = 8\), and \(b = \frac{11}{2}\). Then \(4a + 2b = 4(\frac{5}{2}) + 2(\frac{11}{20}) = 10 + 11 = 21.\)

When we consider \(a - b = 6\) from condition 1) and \(a + b = 8\) from condition 2) and add them together we get \(2a = 14\), and \(a = 7\). Substituting that back into the second equation gives us \(7 + b = 8\), and \(b = 1.\) Then \(4a + 2b = 4(7) + 2(1) = 28 + 2 = 30.\)

Since both conditions together do not yield a unique solution, they are not sufficient.

Therefore, E is the answer.
Answer: E

Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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[GMAT math practice question]

(Algebra) What is the value of \(xy\)?

1) \(x\) is the decimal part of \((2-\sqrt{3})^{2020}\)

2) \(y = (2+\sqrt{3})^{2020}\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary.

Since we have \(2\) variables (\(x\) and \(y\)) and \(0\) equations, C is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)

Since \(2-\sqrt{3}\) is less than \(1\), the decimal part of \((2-\sqrt{3})^{2020}\) is \((2-\sqrt{3})^{2020}\) itself.
Then we have \(xy = (2-\sqrt{3})^{2020}(2+\sqrt{3})^{2020} = (4-3)^{2020} = 1.\)

Since both conditions together yield a unique solution, they are sufficient.

Therefore, C is the answer.
Answer: C

Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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[GMAT math practice question]

(Algebra) If @. is defined as any function, what is the value of 2020 @. 2019?

1) For any x and y, x @ y is defined as x - y.
2) For any x, y and z, x @. x is defined as 0 and x @ (y @ z) is defined as (x @ y) + z.

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
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Since we have 1 variable (the operation @) and 0 equations, D is most likely the answer. So, we should consider each condition on its own first.

Condition 1)
We have 2020 @. 2019 = 2020 – 2019 = 1.
Since condition 1) yields a unique solution, it is sufficient.

Condition 2)
If x = y = z, then x @ (x @ x) = x @ 0, x @ (x @ x) = (x @ x) + x = 0 + x = x and x @ 0 = x.
If y = z, then we have x = x @ 0 = x @ (y @ y) = (x @ y) + y and x @ y = x – y.
Thus we have 2020 @. 2019 = 2020 – 2019 = 1.
Since condition 2) yields a unique solution, it is sufficient.


Note: Tip 1) of the VA method states that D is most likely the answer if condition 1) gives the same information as condition 2).

Therefore, D is the answer.
Answer: D

This question is a CMT 4(B) question: condition 1) is easy to work with, and condition 2) is difficult to work with. For CMT 4(B) questions, D is most likely the answer.

If the original condition includes “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations,” etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A, B, C, or E.
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[GMAT math practice question]

(statistics) The data set \(X\) has \(6\) elements. Its mean is \(0\) and its standard deviation is \(d\), where \(d\) is not zero. When we add a new data element \(x\) to the set \(X\), \(D\) is the standard deviation of the new set of \(7\) elements. Is \(D < d\)?

\(1) |x| < d\)

\(2) x = 0\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary.

Set X={a1, a2, ……, a6}, mean=0 and standard deviation=d. The new set = {a1, a2, ……, a6, x} has standard deviation D. Recall that the standard deviation reflects the distance between each element of the data set and the data set’s average,

Conditions 1)
Since the distance between x and the mean of the set X is less than d, the standard deviation D of the new set is less than d.
Thus, condition 1) is sufficient.

Condition 2)
Since the distance between 0 and the mean of the set X is less than d, the standard deviation D of the new set is less than d.
Thus condition 2) is sufficient.

Therefore, D is the answer.
Answer: D

This question is a CMT4(B) question: condition 2) is easy to work with and condition 1) is difficult to work with. For CMT4(B) questions, D is most likely to be the answer.
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