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Re: The value of (2/3)^99 is closest to which of the following? [#permalink]
yrozenblum wrote:
The value of \((\frac{-2}{3})^{99}\) is closest to which of the following?

A. \(-1\)
B. \(-\frac{1}{2}\)
C. \(0\)
D. \(\frac{1}{2}\)
E. \(1\)

­KarishmaB , Could you please provide your explanation for this one ?
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Re: The value of (2/3)^99 is closest to which of the following? [#permalink]
If you square the fraction just once it is already below half; if you raise to the power of 4 you have 16/81, which is already closer 0 than it is to 1/2. So you can infer that doing so 99 times will be closer to 0 than any other number.
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Re: The value of (2/3)^99 is closest to which of the following? [#permalink]
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yrozenblum wrote:
The value of \((\frac{-2}{3})^{99}\) is closest to which of the following?

A. \(-1\)
B. \(-\frac{1}{2}\)
C. \(0\)
D. \(\frac{1}{2}\)
E. \(1\)


 


Looks like a good candidate for estimation. 

\((\frac{-2}{3})^{99} = (-0.6)^{99}\)

Now note: 0.6*0.6 = 0.36 
0.36*0.6 = 0.216

As we take higher powers of (0.6), the absolute value of the result is reducing. So (0.6)^99 will be a very small number like 0.00...001..
So (-0.6)^99 will simply be - 0.00...001... something that is very close to 0 on the left side of the number line. 
It will certainly be much farther away from 1 or 1/2 or any other such values on the number line. 

Answer (C)
Here is a video on Estimation: https://youtu.be/4Wy7BrQrjkM



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Re: The value of (2/3)^99 is closest to which of the following? [#permalink]
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