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505-555 Level|   Roots|            
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Bunuel
The value of \(\sqrt[3]{-89}\) is:

(A) Between -9 and -10
(B) Between -8 and -9
(C) Between -4 and -5
(D) Between -3 and -4
(E) undefined

\(-5^3 < 89 < -4^3\)

Or, \(-125< - 89 < -64\), Hence, Answer must be (C)
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Why is it C?

Shouldn't be undifined?
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Bunuel
The value of \(\sqrt[3]{-89}\) is:

(A) Between -9 and -10
(B) Between -8 and -9
(C) Between -4 and -5
(D) Between -3 and -4
(E) undefined


3√-5= -125 and 3√-4 = -64
value -89 will lie in between them
IMO C
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Bunuel
The value of \(\sqrt[3]{-89}\) is:

(A) Between -9 and -10
(B) Between -8 and -9
(C) Between -4 and -5
(D) Between -3 and -4
(E) undefined

Since (-4)^3 = -64 and (-5)^3 = -125, the 3rd root of -89 is between -4 and -5.

Answer: C
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Bunuel
The value of \(\sqrt[3]{-89}\) is:

(A) Between -9 and -10
(B) Between -8 and -9
(C) Between -4 and -5
(D) Between -3 and -4
(E) undefined


Important: Recognize that \(-89\) is between \(-64\) and \(-125\)
In other words: \(-125 < -89 < -64\)


Since \((-5)^3 = -125\), we know that \(\sqrt[3]{-125} = -5\)
Since \((-4)^3 = -64\), we know that \(\sqrt[3]{-64} = -4\)

Since \(-89\) is between \(-64\) and \(-125\), we know that \(\sqrt[3]{-89}\) will be between \(\sqrt[3]{-64}\) and \(\sqrt[3]{-125}\)
In other words, \(\sqrt[3]{-89}\) will be between \(-4\) and \(-5\)

Answer: C
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