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18 Jan 2026, 22:00
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D
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Difficulty:
35%
(medium)
Question Stats:
64% (01:10) correct
36%
(01:34)
wrong
based on 86
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The value of a minted coin is directly proportional to its thickness and inversely proportional to its area. What is the value of a coin with radius 10mm and thickness 1mm?
(1) Value of a coin with radius 5 mm and thickness 2mm is $1.
(2) Value of a coin with radius 2.5 mm and thickness 1 mm is $8.
(1) Value of a coin with radius 5 mm and thickness 2mm is $1.
(2) Value of a coin with radius 2.5 mm and thickness 1 mm is $8.
19 Jan 2026, 10:01
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ExpertsGlobal5
Value of a coin V is directly proportional to thickness, & inversely proportional to its Area.
V = K * (T/Area)
T = Thickness of the coin.
Area of a coin = Pi * r^2 , where r is the radius.
V = K*T / ( pi*r^2)
given that: r =10mm and t = 1 mm.
Statement 1:
Value of a coin with radius 5 mm and thickness 2mm is $1.
1 = K*2 / (pi*5*5)
K = (25*pi)/2
For, r =10mm and t = 1 mm.
V = K* 1 / (pi*10*10)
Substitute K = (25*pi)/2 in the above equation, we get
V = (1/8)
Hence, Sufficient
Statement 2:
Value of a coin with radius 2.5 mm and thickness 1 mm is $8.
8 = (k*1)/(pi*2.5*2.5)
k = 8*pi*2.5*2.5
For, r =10mm and t = 1 mm.
V = K* 1 / (pi*10*10)
Substitute K in the above equation, we get
V = (1/2).
Hence, Sufficient
Option D
25 Jan 2026, 02:00
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ExpertsGlobal5
Explanation Video:
