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19 May 2022, 04:15
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
86% (00:56) correct
14%
(01:18)
wrong
based on 44
sessions
History
Date
Time
Result
Not Attempted Yet
The vertices of a triangle are (2, 1), (2, 5), and (5, 1). The area of the triangle is
(A) 12
(B) 10
(C) 8
(D) 6
(E) 5
(A) 12
(B) 10
(C) 8
(D) 6
(E) 5
genericUser
Joined: 31 Jan 2022
Last visit: 22 Dec 2023
Posts: 111
Own Kudos:
Given Kudos: 35
Location: Italy
Schools: SDA Bocconi "24 (M)
GMAT 1: 670 Q49 V33
GMAT 2: 690 Q47 V37
GPA: 3.9
19 May 2022, 09:09
Kudos
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The vertices of a triangle are (2, 1), (2, 5), and (5, 1). The area of the triangle is
(A) 12
(B) 10
(C) 8
(D) 6
(E) 5
from attachments
\(base*heigth*0.5=3*4*0.5=6\)
(A) 12
(B) 10
(C) 8
(D) 6
(E) 5
from attachments
\(base*heigth*0.5=3*4*0.5=6\)
Attachments
tri.png [ 8.16 KiB | Viewed 1375 times ]
19 May 2022, 09:28
Kudos
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The vertices of a triangle are (2, 1), (2, 5), and (5, 1). The area of the triangle is
(A) 12
(B) 10
(C) 8
(D) 6
(E) 5
IMO D
(2, 1), (2, 5) = length of this side =4
the x co-ordinate is constant thus we need to find the difference in Y axis only
(2, 1), (5, 1) =length of this side =3
the y-co-ordinate is constant this we need to find the difference between X axis only
(2, 5) (5, 1) = length of the side = 5
As the above 2 sides are perpendicular to each other , and this side is the hypotenuse
Area is 1/2*4*3 =6
(A) 12
(B) 10
(C) 8
(D) 6
(E) 5
IMO D
(2, 1), (2, 5) = length of this side =4
the x co-ordinate is constant thus we need to find the difference in Y axis only
(2, 1), (5, 1) =length of this side =3
the y-co-ordinate is constant this we need to find the difference between X axis only
(2, 5) (5, 1) = length of the side = 5
As the above 2 sides are perpendicular to each other , and this side is the hypotenuse
Area is 1/2*4*3 =6
