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HKD1710
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HKD1710
The \((x, y)\) pair \((-1, 1)\) satisfies which of the following equations?

I. \(2x^3 - y^2 = -3\)
II. \(2x^2 - y^3 = 1\)
III. \(x^2 - 2y^3 = -1\)

(A) I only
(B) I and II only
(C) I and III only
(D) II and III only
(E) I, II, and III
 
Hi HKD1710

why in equation

I. \(2x^3 - y^2 = -3\)

\(- y^2\) = -1 and not +1?

I know there is some reason behind that but don't know what it is. Could you please assist.­
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HKD1710
The \((x, y)\) pair \((-1, 1)\) satisfies which of the following equations?

I. \(2x^3 - y^2 = -3\)
II. \(2x^2 - y^3 = 1\)
III. \(x^2 - 2y^3 = -1\)

(A) I only
(B) I and II only
(C) I and III only
(D) II and III only
(E) I, II, and III
 
Hi HKD1710

why in equation

I. \(2x^3 - y^2 = -3\)

\(- y^2\) = -1 and not +1?

I know there is some reason behind that but don't know what it is. Could you please assist.
\(y=1\)

\(y^2 = 1^2\)

\(y^2 = 1\)

\(- y^2 = - 1\)­
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HKD1710

Gmatprep550

HKD1710
The \((x, y)\) pair \((-1, 1)\) satisfies which of the following equations?

I. \(2x^3 - y^2 = -3\)
II. \(2x^2 - y^3 = 1\)
III. \(x^2 - 2y^3 = -1\)

(A) I only
(B) I and II only
(C) I and III only
(D) II and III only
(E) I, II, and III
 
Hi HKD1710

why in equation

I. \(2x^3 - y^2 = -3\)

\(- y^2\) = -1 and not +1?

I know there is some reason behind that but don't know what it is. Could you please assist.
\(y=1\)

\(y^2 = 1^2\)

\(y^2 = 1\)

\(- y^2 = - 1\)

But \(- y^2\) also = - y * - y =- 1 * - 1 which = + 1 hence would like to know when to follow above method described by you. I am sure we will follow that if \(y^2\) would have provided in bracket for ex \(-(y^2)\)

Hope you are getting where I am getting confused.

Thanks !­
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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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HKD1710
Gmatprep550
The \((x, y)\) pair \((-1, 1)\) satisfies which of the following equations?

I. \(2x^3 - y^2 = -3\)
II. \(2x^2 - y^3 = 1\)
III. \(x^2 - 2y^3 = -1\)

(A) I only
(B) I and II only
(C) I and III only
(D) II and III only
(E) I, II, and III



Hi HKD1710

why in equation

I. \(2x^3 - y^2 = -3\)

\(- y^2\) = -1 and not +1?

I know there is some reason behind that but don't know what it is. Could you please assist.

\(y=1\)

\(y^2 = 1^2\)

\(y^2 = 1\)

\(- y^2 = - 1\)


But \(- y^2\) also = - y * - y =- 1 * - 1 which = + 1 hence would like to know when to follow above method described by you. I am sure we will follow that if \(y^2\) would have provided in bracket for ex \(-(y^2)\)

Hope you are getting where I am getting confused.

Thanks !

No. \(-y^2=-(y*y)\). On the other hand \((-y)*(-y) = y^2\).
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I am wondering why \(-1^2 = +1\) where as \(-Y^2 = -(Y*Y)\)?
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I am wondering why \(-1^2 = +1\) where as \(-Y^2 = -(Y*Y)\)?

\(-1^2=-(1^2) =-1\), while \((-1)^2=1\).
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simply plugin for x,y (-1,1) ; all options are valid
IMO E
HKD1710
The \((x, y)\) pair \((-1, 1)\) satisfies which of the following equations?

I. \(2x^3 - y^2 = -3\)
II. \(2x^2 - y^3 = 1\)
III. \(x^2 - 2y^3 = -1\)

(A) I only
(B) I and II only
(C) I and III only
(D) II and III only
(E) I, II, and III
 
­
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HKD1710
The \((x, y)\) pair \((-1, 1)\) satisfies which of the following equations?

I. \(2x^3 - y^2 = -3\)
II. \(2x^2 - y^3 = 1\)
III. \(x^2 - 2y^3 = -1\)

(A) I only
(B) I and II only
(C) I and III only
(D) II and III only
(E) I, II, and III
 
Plug in the values \((-1, 1)\) in all the options (I), (II) & (III) , all satisfies, Answer must be (E)­
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