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30 Jan 2019, 04:42
Kudos
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
59% (01:35) correct
41%
(01:53)
wrong
based on 516
sessions
History
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Not Attempted Yet
There are 12 red balls, 10 blue balls, 15 green balls and 9 black balls in a bag. What is the minimum number of balls to be taken out of the bag to assure that you have all the balls of one color?
A. 10
B. 16
C. 23
D. 42
E. 43
A. 10
B. 16
C. 23
D. 42
E. 43
30 Jan 2019, 04:43
Kudos
Bookmarks
Bunuel
There are 12 red balls, 10 blue balls, 15 green balls and 9 black balls in a bag. What is the minimum number of balls to be taken out of the bag to assure that you have all the balls of one color?
A. 10
B. 16
C. 23
D. 42
E. 43
A. 10
B. 16
C. 23
D. 42
E. 43
The worst-case scenario would be if we pick 11 red balls, 9 blue balls, 14 green balls, and 8 black balls. In this case, we'll have 11+9+14+8=42 balls and still won't have all the balls of one color. The next ball, the 43rd one we pick, no matter which color it is, will guarantee that we have all the balls of one color.
Answer: E.
General Discussion
30 Jan 2019, 05:06
Kudos
Bookmarks
Bunuel
There are 12 red balls, 10 blue balls, 15 green balls and 9 black balls in a bag. What is the minimum number of balls to be taken out of the bag to assure that you have all the balls of one color?
A. 10
B. 16
C. 23
D. 42
E. 43
A. 10
B. 16
C. 23
D. 42
E. 43
In other words, the worst case is when the last 4 are all of different colour, and the one you pick will result in picking all of one type, so ans = 12+10+15+9-4+1=43
