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There are 120 televisions on display at an electronics
store. The number of televisions displaying sports programs
is 50% less than 4 times the number of televisions
displaying educational programs. 1/4 of the televisions are
displaying neither sports programs nor educational programs.
If all of the 120 televisions are displaying programs, how
many televisions are displaying sports programs?
A. 30
B. 24
C. 45
D. 40
E. 60
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There are 120 televisions on display at an electronics store. The number of televisions displaying sports programs is 50% less than 4 times the number of televisions displaying educational programs. 1/4 of the televisions are displaying neither sports programs nor educational programs. If all of the 120 televisions are displaying programs, how many televisions are displaying sports programs?
A. 30 B. 24 C. 45 D. 40 E. 60
Show more
Solving for this directly gives us 60 TVs showing sports. But what scares me is the part in bold.
but again solving for the numbers also gives 60 as the answer.
S = number of TVs displaying sports programs
E = number of TVs displaying educational programs
O = number of TVs displaying other programs
S + E + O = 120
Since 1/4 of the televisions are displaying neither sports
programs nor educational program, O is 30. Thus,
S + E + 30 = 120
S + E = 90
Since the number of TVs displaying sports programs is 50%
less than 4 times the number of TVs displaying educational
programs, we can set up the following equation:
S = .50(4E)
S = 2E
Substituting the value of S into the previous equation:
2E + E = 90
3E = 90
E = 30
Substituting E into the equation S = 2E:
S = 2(30)
S = 60
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.