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There are 200 female managers in a certain company. Find the

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There are 200 female managers in a certain company. Find the [#permalink]

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New post 09 Nov 2012, 10:54
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There are 200 female managers in a certain company. Find the total number of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers.

(A) 300
(B) 400
(C) 500
(D) 600
(E) None of these
[Reveal] Spoiler: OA

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Re: There are 200 female managers in a certain company. Find the [#permalink]

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New post 09 Nov 2012, 13:28
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Albeit, you can draw Venn diagram and table to expound upon it meticulously, I think you can straightforwardly do this:
as per question stem 2/5M (Portion of Men employees who are managers) + 200 (Portion of Female employees who are managers) = 2/5T (Portion of Total number of employees who are managers), thus we get that 2/5M+200 = 2/5T, or 2/5(T-M)=200, from here we get that T-M=500, that would be total number of female employees and the answer (C)
Feel free to correct me, if I went awry
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New post 09 Nov 2012, 13:31
Could some one solve this question please

I tried a few ways and couldn't get to the bottom of it

so far
200 Female Manager = 3/5 x 2/5 of X
X = 833 (total men and women)

3/5 is non manager > 3/5 x 833 = 499 ~
So how could i work out what's the female part of non manager group

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Re: There are 200 female managers in a certain company. Find the [#permalink]

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New post 09 Nov 2012, 23:31
chibimoon wrote:
Could some one solve this question please

I tried a few ways and couldn't get to the bottom of it

so far
200 Female Manager = 3/5 x 2/5 of X
X = 833 (total men and women)

3/5 is non manager > 3/5 x 833 = 499 ~
So how could i work out what's the female part of non manager group


YOU CAN ALSO SOLVE THIS PROBLEM BY THIS WAY
SUPPOSE TOTAL EMPLOYEE = 1000
MANAGER = 1000*2/5=400(F=200,M=200),THEN TOTAL FEMALE =
2/5.....200
1........5*200/2 =500

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Re: There are 200 female managers in a certain company. Find the [#permalink]

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derekgmat wrote:
There are 200 female managers in a certain company. Find the total number of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers.

(A) 300
(B) 400
(C) 500
(D) 600
(E) None of these


{Managers} = {Female Managers} + {Male Managers};

We are told that the total number of managers in the company is 2/5 of all the employees , thus {Managers} = 2/5 (M + F), where M and F are number of female and male employees, respectively.

Also, we know that 2/5 of all male employees are managers: {Male Managers} = 2/5 * M as well as there are total of 200 female managers: {Female Managers} = 200;

Thus: 2/5 (M + F) = 200 + 2/5 * M --> F = 500.

Answer: C.

Check almost similar question written as DS problem:
if-2-5-of-the-students-at-college-c-are-business-majors-wha-135545.html

Hope it helps.
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Re: There are 200 female managers in a certain company. Find the [#permalink]

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New post 11 Nov 2012, 23:14
In my opinion the best way to solve such questions is tabling (see below)

Managers Non-managers Total
Female 200 (x-y)-200 x-y
Male 2/5y 3/5y Y
Total 2/5x 3/5x X

So it is not necessary to solve for each cell, we just need to find the value of x-y. From the table we see that 2/5x-2/5y=200, 2(x-y)/5=200, 2(x-y)=1000, x-y=500, so our answer is 500, which is C

Hope that helps.
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Re: There are 200 female managers in a certain company. Find the [#permalink]

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New post 18 Aug 2013, 06:31
Encircled in the diagram is the value to be calculated:

So by forming equations from the diagram:

(2/5)X - (2/5)Y = 200

(X-Y) = 200*5/2 = 500
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Re: There are 200 female managers in a certain company. Find the [#permalink]

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New post 18 Aug 2013, 13:33
derekgmat wrote:
There are 200 female managers in a certain company. Find the total number of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers.

(A) 300
(B) 400
(C) 500
(D) 600
(E) None of these


Here,

Total = M+F
And managers = 2/5 (M+F) again male managers = 2/5 M
so, 200 + 2/5 M = 2/5 (M+F)
or, 1000 + 2 M = 2M + 2F
or, F = 500 (Answer C)
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Re: There are 200 female managers in a certain company. Find the [#permalink]

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New post 01 Jul 2016, 20:04
It couldnt get any easier to solve with the explanation shared by Bunuel.

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Re: There are 200 female managers in a certain company. Find the [#permalink]

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Re: There are 200 female managers in a certain company. Find the [#permalink]

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New post 04 Sep 2017, 10:30
My answer is C.

We can actually solve this question orally.
I thought of it like this:-
Let total no. of employees be T.
T= F+M. No. of females + No. of males
No. of managers= 2/5 of T
= 2/5(F+M)
=2/5 F + 2/5 M

Thus, female managers = 2/5 F
Given, female employees = 200.

Equating both.
Total no. of female employees = 500.

Hope it helps.


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Re: There are 200 female managers in a certain company. Find the   [#permalink] 04 Sep 2017, 10:30
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