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There are 200 female managers in a certain company. Find the [#permalink]
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09 Nov 2012, 10:54
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There are 200 female managers in a certain company. Find the total number of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers. (A) 300 (B) 400 (C) 500 (D) 600 (E) None of these
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Re: There are 200 female managers in a certain company. Find the [#permalink]
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09 Nov 2012, 13:28
Albeit, you can draw Venn diagram and table to expound upon it meticulously, I think you can straightforwardly do this: as per question stem 2/5M (Portion of Men employees who are managers) + 200 (Portion of Female employees who are managers) = 2/5T (Portion of Total number of employees who are managers), thus we get that 2/5M+200 = 2/5T, or 2/5(TM)=200, from here we get that TM=500, that would be total number of female employees and the answer (C) Feel free to correct me, if I went awry
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Re: There are 200 female managers in a certain company. Find the [#permalink]
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09 Nov 2012, 13:31
Could some one solve this question please
I tried a few ways and couldn't get to the bottom of it
so far 200 Female Manager = 3/5 x 2/5 of X X = 833 (total men and women)
3/5 is non manager > 3/5 x 833 = 499 ~ So how could i work out what's the female part of non manager group



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Re: There are 200 female managers in a certain company. Find the [#permalink]
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09 Nov 2012, 23:31
chibimoon wrote: Could some one solve this question please
I tried a few ways and couldn't get to the bottom of it
so far 200 Female Manager = 3/5 x 2/5 of X X = 833 (total men and women)
3/5 is non manager > 3/5 x 833 = 499 ~ So how could i work out what's the female part of non manager group YOU CAN ALSO SOLVE THIS PROBLEM BY THIS WAY SUPPOSE TOTAL EMPLOYEE = 1000 MANAGER = 1000*2/5=400(F=200,M=200),THEN TOTAL FEMALE = 2/5.....200 1........5*200/2 =500



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Re: There are 200 female managers in a certain company. Find the [#permalink]
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10 Nov 2012, 04:24
derekgmat wrote: There are 200 female managers in a certain company. Find the total number of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers.
(A) 300 (B) 400 (C) 500 (D) 600 (E) None of these {Managers} = {Female Managers} + {Male Managers}; We are told that the total number of managers in the company is 2/5 of all the employees , thus {Managers} = 2/5 (M + F), where M and F are number of female and male employees, respectively. Also, we know that 2/5 of all male employees are managers: {Male Managers} = 2/5 * M as well as there are total of 200 female managers: {Female Managers} = 200; Thus: 2/5 (M + F) = 200 + 2/5 * M > F = 500. Answer: C. Check almost similar question written as DS problem: if25ofthestudentsatcollegecarebusinessmajorswha135545.htmlHope it helps.
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Re: There are 200 female managers in a certain company. Find the [#permalink]
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11 Nov 2012, 23:14
In my opinion the best way to solve such questions is tabling (see below) Managers Nonmanagers Total Female 200 (xy)200 xy Male 2/5y 3/5y Y Total 2/5x 3/5x X So it is not necessary to solve for each cell, we just need to find the value of xy. From the table we see that 2/5x2/5y=200, 2(xy)/5=200, 2(xy)=1000, xy=500, so our answer is 500, which is C Hope that helps.
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Re: There are 200 female managers in a certain company. Find the [#permalink]
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18 Aug 2013, 06:31
Encircled in the diagram is the value to be calculated: So by forming equations from the diagram: (2/5)X  (2/5)Y = 200 (XY) = 200*5/2 = 500
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Re: There are 200 female managers in a certain company. Find the [#permalink]
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18 Aug 2013, 13:33
derekgmat wrote: There are 200 female managers in a certain company. Find the total number of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers.
(A) 300 (B) 400 (C) 500 (D) 600 (E) None of these Here, Total = M+F And managers = 2/5 (M+F) again male managers = 2/5 M so, 200 + 2/5 M = 2/5 (M+F) or, 1000 + 2 M = 2M + 2F or, F = 500 (Answer C)
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Re: There are 200 female managers in a certain company. Find the [#permalink]
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01 Jul 2016, 20:04
It couldnt get any easier to solve with the explanation shared by Bunuel.



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Re: There are 200 female managers in a certain company. Find the [#permalink]
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04 Sep 2017, 10:30
My answer is C.
We can actually solve this question orally. I thought of it like this: Let total no. of employees be T. T= F+M. No. of females + No. of males No. of managers= 2/5 of T = 2/5(F+M) =2/5 F + 2/5 M
Thus, female managers = 2/5 F Given, female employees = 200.
Equating both. Total no. of female employees = 500.
Hope it helps.
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