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If 2/5 of the students at College C are business majors, wha

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If 2/5 of the students at College C are business majors, wha  [#permalink]

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New post 09 Jul 2012, 03:43
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If 2/5 of the students at College C are business majors, what is the number of female students at College C?

(1) 2/5 of the male students at College C are business majors.
(2) 200 of the female students at College C are business majors.

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Re: If 2/5 of the students at College C are business majors, wha  [#permalink]

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New post 09 Jul 2012, 04:02
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If 2/5 of the students at College C are business majors, what is the number of female students at College C?

Given: 2/5(Female+Male)=Business Majors. Question: Female=?

(1) 2/5 of the male students at College C are business majors --> 2/5*M=Male Business Majors. Not sufficient.

(2) 200 of the female students at College C are business majors --> Female Business Majors=200. Not sufficient.

(1)+(2) {Business Majors}={Male Business Majors}+{Female Business Majors} --> 2/5(F+M)=2/5*M+200 --> 2/5*F=200 --> F=500. Sufficient.

Answer: C.
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Re: If 2/5 of the students at College C are business majors, wha  [#permalink]

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New post 09 Jul 2012, 04:09
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C it is.

Given: 2/5 students Business majors

1. 2/5 BM = Male . =>3/5 of BM Female. Insuff
2. BM Female = 300

c combine the two 300=(2/5)(3/5) Students
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Re: If 2/5 of the students at College C are business majors, wha  [#permalink]

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New post 10 Jul 2012, 08:07
Bunuel wrote:
If 2/5 of the students at College C are business majors, what is the number of female students at College C?

Given: 2/5(Female+Male)=Business Majors. Question: Female=?

(1) 2/5 of the male students at College C are business majors --> 2/5*M=Male Business Majors. Not sufficient.

(2) 200 of the female students at College C are business majors --> Female Business Majors=200. Not sufficient.

(1)+(2) {Business Majors}={Male Business Majors}+{Female Business Majors} --> 2/5(F+M)=2/5*M+200 --> 2/5*F=200 --> F=500. Sufficient.

Answer: C.


Based on what you put for (2), (2/5)(Females) = 200, therefore Females = (5/2)(200) = 500. Why bother tangling it with the males? We already know from the question that (2/5)(Males + Females) = business majors and statement 1 is just a repeat of what is given.
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Re: If 2/5 of the students at College C are business majors, wha  [#permalink]

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New post 10 Jul 2012, 08:20
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Injuin wrote:
Bunuel wrote:
If 2/5 of the students at College C are business majors, what is the number of female students at College C?

Given: 2/5(Female+Male)=Business Majors. Question: Female=?

(1) 2/5 of the male students at College C are business majors --> 2/5*M=Male Business Majors. Not sufficient.

(2) 200 of the female students at College C are business majors --> Female Business Majors=200. Not sufficient.

(1)+(2) {Business Majors}={Male Business Majors}+{Female Business Majors} --> 2/5(F+M)=2/5*M+200 --> 2/5*F=200 --> F=500. Sufficient.

Answer: C.


Based on what you put for (2), (2/5)(Females) = 200, therefore Females = (5/2)(200) = 500. Why bother tangling it with the males? We already know from the question that (2/5)(Males + Females) = business majors and statement 1 is just a repeat of what is given.


There was a typo.

From (2): 200 of the female students at College C are business majors --> Female Business Majors=200. Not (2/5)(Females) = 200.
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Re: If 2/5 of the students at College C are business majors, wha  [#permalink]

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New post 10 Jul 2012, 08:28
I hope you will be patient with me since it's been a long morning, but here is my reasoning, even after sifting through the various related threads:

We are given that 2/5 of the students are business majors so (2/5)(Males+Females) = Business majors. Expanded, we have Business majors = (2/5)(Males)+(2/5)(Females) = Business majors. Therefore 2/5 males are business majors and 2/5 females are business majors.

Statement 1 just repeats that (2/5)(Males) are business majors

Statement 2 says that 200 females are business majors. We can equate that (2/5)(Females) = 200 from the expanded information provided and have the final form be Females = (5/2)(200) = 500.

For the life of me I cannot see how statement 2 is insufficient unless I am confused about how the information they gave us is constructed as stated.
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Re: If 2/5 of the students at College C are business majors, wha  [#permalink]

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New post 10 Jul 2012, 08:40
Injuin wrote:
I hope you will be patient with me since it's been a long morning, but here is my reasoning, even after sifting through the various related threads:

We are given that 2/5 of the students are business majors so (2/5)(Males+Females) = Business majors. Expanded, we have Business majors = (2/5)(Males)+(2/5)(Females) = Business majors. Therefore 2/5 males are business majors and 2/5 females are business majors.

Statement 1 just repeats that (2/5)(Males) are business majors

Statement 2 says that 200 females are business majors. We can equate that (2/5)(Females) = 200 from the expanded information provided and have the final form be Females = (5/2)(200) = 500.

For the life of me I cannot see how statement 2 is insufficient unless I am confused about how the information they gave us is constructed as stated.


The red part is not correct. 2/5 (40%) of the students are business majors does not mean that 40% of males and 40% of females are business majors.

For example: say there are 300 males and 200 females (total of 500 students), then there will be 2/5*500=200 business majors. So, it could be that 100% of females and 0% of males are business majors.

Hope it's clear.
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Re: If 2/5 of the students at College C are business majors, wha  [#permalink]

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New post 10 Jul 2012, 08:55
I can see how that situation will make what I said incorrect, but then I do not know how I would setup a question like this in the future. I was under the impression that students = males + females. Therefore if 2/5 students are business majors, then 2/5 (males + females) are business majors. What rule did I violate to cause me to tunnel vision into thinking that the aforementioned equation could be expanded into (2/5)(males) + (2/5)(females)?
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Re: If 2/5 of the students at College C are business majors, wha  [#permalink]

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New post 10 Jul 2012, 08:58
Injuin wrote:
I can see how that situation will make what I said incorrect, but then I do not know how I would setup a question like this in the future. I was under the impression that students = males + females. Therefore if 2/5 students are business majors, then 2/5 (males + females) are business majors. What rule did I violate to cause me to tunnel vision into thinking that the aforementioned equation could be expanded into (2/5)(males) + (2/5)(females)?


Again: 2/5(Female+Male)=Business Majors CAN be expanded as 2/5*F+2/5*M=Business Majors, but it does not mean that 2/5 of males and 2/5 of females are business majors.
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Re: If 2/5 of the students at College C are business majors, wha  [#permalink]

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New post 10 Jul 2012, 09:01
Ah, I ended up thinking of variables as words. Thank you for the clarification.
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Re: If 2/5 of the students at College C are business majors, wha  [#permalink]

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New post 11 Feb 2017, 23:21
Assume male students =X
Female students = y

total Biz majors = (2/5)(X+y)
non-Biz majors =(1- 2/5)(X+Y) = (3/5)(x+y)

statement 1: 2/5 of males students are business majors ..which means 3/5 of male students are non-business majors
= 3X/5
non-biz females=(3/5)(X+Y)-3X/5=(3/5)Y

no information on actual number of students

not sufficient

statement 2: 200 female students are business majors.

no information on non-biz majors female students

not sufficient

statement 1&2: 3/5 of male students are non-biz majors and 200 female students are biz majors
non-biz females= (3/5)Y
biz females = Y-(3/5)Y=(2/5)Y
(2/5)Y=200
=>Y=500
thus females are 500


sufficient

Hence C
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If 2/5 of the students at College C are business majors, wha  [#permalink]

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New post 09 May 2019, 17:57
Stiv wrote:
If 2/5 of the students at College C are business majors, what is the number of female students at College C?

(1) 2/5 of the male students at College C are business majors.
(2) 200 of the female students at College C are business majors.


Look at Picture:
Statement 1: Not Enough Info, but we can infer that Total Females = (X-Y)
Statement 2: Not Enough Info

Both statements Together:

\(\frac{2}{5}\)Y + 200 = \(\frac{2}{5}\)X

200 = \(\frac{2}{5}X\) - \(\frac{2}{5}Y\) (Factor out \(\frac{2}{5}\))

200 = \(\frac{2}{5}(X-Y)\)

\(200*\frac{5}{2} = (X-Y)\)

\(500 = (X-Y)\)
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If 2/5 of the students at College C are business majors, wha   [#permalink] 09 May 2019, 17:57
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