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Bunuel
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There are 3 teams each with 5 basket players. How many combinations ar 11 Jun 2019, 01:32
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

35% (medium)

Question Stats:

69% (01:53) correct 31% (02:07) wrong based on 275 sessions

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There are 3 teams each with 5 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?

A. 50
B. 23
C. 75
D. 28
E. 45
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C
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CareerGeek
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There are 3 teams each with 5 basket players. How many combinations ar 11 Jun 2019, 05:44
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Bunuel
There are 3 teams each with 5 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?

A. 50
B. 23
C. 75
D. 28
E. 45
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First select any 2 teams out of 3 = 3c2 ways

Now from the 2 teams select 1 player each = 5c1*5c1

So, total ways = 3c1*5c1*5c1 = 75 ways

IMO Option C

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There are 3 teams each with 5 basket players. How many combinations ar 11 Jun 2019, 02:32
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Bunuel
There are 3 teams each with 5 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?

A. 50
B. 23
C. 75
D. 28
E. 45
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Total Combinations - 2 players from same team combinations; 15C2-3*5C2=105-30=75 IMO Option C
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There are 3 teams each with 5 basket players. How many combinations ar 11 Jun 2019, 11:10
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Bunuel
There are 3 teams each with 5 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?

A. 50
B. 23
C. 75
D. 28
E. 45
Show more

total ways ; 15c2 = 105
for 3 teams 5 players; 5c2* 3; 30
105-30 ; 75
IMO c
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There are 3 teams each with 5 basket players. How many combinations ar 06 Jul 2019, 18:39
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3 teams with 5 players each- 5 5 5
Total players = 15

To select the first player, we have 15 choices.
To select the second one, we have 10 choices (due to the constraint that two players cannot belong to the same team)

Because it's "selection" we divide by 2! --> 15*10/2 = 75
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There are 3 teams each with 5 basket players. How many combinations ar 17 Jul 2020, 10:26
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