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There are 30 people and 3 clubs M, S, and Z in a company. 10 people jo

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There are 30 people and 3 clubs M, S, and Z in a company. 10 people jo  [#permalink]

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New post 12 Jul 2011, 22:26
4
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

75% (01:39) correct 25% (01:39) wrong based on 71 sessions

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There are 30 people and 3 clubs M, S, and Z in a company. 10 people joined M, 12 people joined S and 5 people joined Z. If the members of M did not join any other club, at most, how many people of the company did not join any club?

A: 4
B: 5
C: 6
D: 7
E: 8
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Re: There are 30 people and 3 clubs M, S, and Z in a company. 10 people jo  [#permalink]

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New post 12 Jul 2011, 22:44
Answer E.

key is 'atmost' here.

so 10 people joined M.

12 people joined S and 5 people joined Z. to get maximum people who did not join any club, 5 people who joined Z are among 12 people who joined S.

so 12+10 = 22
30-22 = 8
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Re: There are 30 people and 3 clubs M, S, and Z in a company. 10 people jo  [#permalink]

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New post 15 Mar 2018, 04:36
If the problem asked "at minimum" instead of "at most" were the answer 3 people?

Thanks to everyone, I am trying to deepen my knowledge about sets problems :)
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Re: There are 30 people and 3 clubs M, S, and Z in a company. 10 people jo  [#permalink]

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New post 15 Mar 2018, 05:30
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MvArrow wrote:
If the problem asked "at minimum" instead of "at most" were the answer 3 people?

Thanks to everyone, I am trying to deepen my knowledge about sets problems :)


Hey MvArrow ,

Yes, your thinking is correct. If you are saying all the members are not joining any other club, then you will have people who didn't join any club = 30 - (10+12+5) = 3

Does that make sense?
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Re: There are 30 people and 3 clubs M, S, and Z in a company. 10 people jo  [#permalink]

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New post 15 Mar 2018, 07:14
abhimahna wrote:
MvArrow wrote:
If the problem asked "at minimum" instead of "at most" were the answer 3 people?

Thanks to everyone, I am trying to deepen my knowledge about sets problems :)


Hey MvArrow ,

Yes, your thinking is correct. If you are saying all the members are not joining any other club, then you will have people who didn't join any club = 30 - (10+12+5) = 3

Does that make sense?


Sure! Thanks for confirming my reasoning :)
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Re: There are 30 people and 3 clubs M, S, and Z in a company. 10 people jo  [#permalink]

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New post 19 Mar 2018, 06:37
Alchemist1320 wrote:
There are 30 people and 3 clubs M, S, and Z in a company. 10 people joined M, 12 people joined S and 5 people joined Z. If the members of M did not join any other club, at most, how many people of the company did not join any club?

A: 4
B: 5
C: 6
D: 7
E: 8


To find the maximum number of people of the company who did not join any club, we can assume that all 5 people who joined club Z also joined club S. Since 10 people joined club M (and no other clubs) and 12 people joined club S or club Z or both, we have 10 + 12 = 22 people who joined at least one club. Thus, at most, 30 - 22 = 8 people did not join any club.

Answer: E
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Re: There are 30 people and 3 clubs M, S, and Z in a company. 10 people jo  [#permalink]

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New post 27 Mar 2018, 00:46
can someone let me know where is my understanding of this problem incorrect.
Now when the question is saying that the members of M didnt join any other club then there are 10 people who didnt join s or z . so only M is 10. Im i correct?
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Re: There are 30 people and 3 clubs M, S, and Z in a company. 10 people jo   [#permalink] 27 Mar 2018, 00:46
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