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novase101
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There are 30 people and 3 clubs M, S, and Z in a company. 10 08 Apr 2006, 20:14
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There are 30 people and 3 clubs M, S, and Z in a company. 10 people joined M, 12 people joined S and 5 people joined Z. If the members of M did not join any other club, at most, how many people of the company did not join any club?

A. 4
B. 5
C. 6
D. 7
E. 8

Please explain rationale. Thanks.



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bewakoof
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There are 30 people and 3 clubs M, S, and Z in a company. 10 08 Apr 2006, 20:19
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novase101
There are 30 people and 3 clubs M, S, and Z in a company. 10 people joined M, 12 people joined S and 5 people joined Z. If the members of M did not join any other club, at most, how many people of the company did not join any club?

A. 4
B. 5
C. 6
D. 7
E. 8

Please explain rationale. Thanks.
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atmost 8...

30 -10 -12
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novase101
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There are 30 people and 3 clubs M, S, and Z in a company. 10 08 Apr 2006, 20:32
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Ok...so you are essentially using the equation 30-10-7-5 where the 5 members of club Z are actually those that joined both S and Z.
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gmat_crack
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There are 30 people and 3 clubs M, S, and Z in a company. 10 08 Apr 2006, 23:04
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bewakoof
novase101
There are 30 people and 3 clubs M, S, and Z in a company. 10 people joined M, 12 people joined S and 5 people joined Z. If the members of M did not join any other club, at most, how many people of the company did not join any club?

A. 4
B. 5
C. 6
D. 7
E. 8

Please explain rationale. Thanks.

atmost 8...

30 -10 -12
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Agree with it.
its 8 because question is asking most value.
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jodeci
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There are 30 people and 3 clubs M, S, and Z in a company. 10 08 Apr 2006, 23:12
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gmat_crack
bewakoof
novase101
There are 30 people and 3 clubs M, S, and Z in a company. 10 people joined M, 12 people joined S and 5 people joined Z. If the members of M did not join any other club, at most, how many people of the company did not join any club?

A. 4
B. 5
C. 6
D. 7
E. 8

Please explain rationale. Thanks.

atmost 8...

30 -10 -12

Agree with it.
its 8 because question is asking most value.
Show more


At least I did not understand anything in this question; could somebody explain why 5 and 12 are not taken independently as in

30=10+12+5-Both+3 is not applicable. The question I assume did not tell us the Both thing

Thanks



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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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Thank you for understanding, and happy exploring!