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14 Jul 2013, 11:07
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C
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Difficulty:
35%
(medium)
Question Stats:
67% (01:33) correct
33%
(01:36)
wrong
based on 141
sessions
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There are 35 distinct numbers in set M, there are 28 distinct numbers in set N, and there are 12 distinct numbers that are in both sets M and N. Set H is the set containing the elements that are in at least one of sets M and N. How many elements are in set H?
A. 39
B. 40
C. 51
D. 58
E. 63
A. 39
B. 40
C. 51
D. 58
E. 63
14 Jul 2013, 11:14
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antoxavier
There are 35 distinct numbers in set M, there are 28 distinct numbers in set N, and there are 12 distinct numbers that are in both sets M and N. Set H is the set containing the elements that are in at least one of sets M and N. How many elements are in set H?
A. 39
B. 40
C. 51
D. 58
E. 63
Official answer not available
A. 39
B. 40
C. 51
D. 58
E. 63
Official answer not available
{Total} = {M} + {N} - {Both}
{Total} = 35 + 28 - 12 = 51.
Answer: C.
14 Aug 2013, 09:37
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Bunuel
antoxavier
There are 35 distinct numbers in set M, there are 28 distinct numbers in set N, and there are 12 distinct numbers that are in both sets M and N. Set H is the set containing the elements that are in at least one of sets M and N. How many elements are in set H?
A. 39
B. 40
C. 51
D. 58
E. 63
Official answer not available
A. 39
B. 40
C. 51
D. 58
E. 63
Official answer not available
{Total} = {M} + {N} - {Both}
{Total} = 35 + 28 - 12 = 51.
Answer: C.
Are you sure?
at least in one of the sets could mean either M or N or both. therefore 63 should be ok.
Let me know what you think.
Regards,
Marco
