dave13 wrote:
sairam595 wrote:
There are 4 bottles with the same number balls m respectively. If balls from only the 1-st bottle are moved to the other 3 bottles and finally the ratio of the numbers of balls in the bottles is 1 : 6 : 5 : 4, what fraction does the moved balls represent in terms of m?
A. m/4
B. m/2
C. 3m/4
D. m
E. 4m/5
I wonder if this approach is correct
1 : 6 : 5 : 4 imagine there are 1, 6, 5 and 4 bottles after removing balla from the first one
so bottle 1 has 1 ball
bottle 2 has 6 balls (5 balls were moved into it)
bottle 3 has 5 balls (4 balles were moved)
bottle 4 has 4 balls (3 balls were moved)
Number of moved balls 5+4+3 =12
Total number of balls 16
Hence \(\frac{12}{16}\) = \(\frac{3}{4}\)
pushpitkc is my reasoning correct
Hi
dave13Unfortunately, the solution that you have used is wrong.
What's important to understand is that the number of balls is equal in each bottle
is the same, to begin with. All 4 bottles must have m balls each. Let that number be 4.
Now, that balls move from the first bottle to other 3 bottles and we need a ratio - 1:6:5:4
This will happen when 3 balls are moved from bottle 1 - 2 balls into bottle 2 and 1 ball into bottle 3.
Bottle 1: 4 - 3 = 1 | Bottle 2: 4 + 2 = 6 | Bottle 3: 4 + 1 = 5 | Bottle 4: 4 + 0 = 4 (Ratio - 1:6:5:4)
Therefore, the fraction of balls moved is 3m/4 as 3 balls are moved from Bottle 1(when m=4)
Hope that helps!
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