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28 Jan 2022, 04:50
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There are 6 cards numbered from 1 to 6. They are placed into a box, and then one is drawn and put back and then another card is drawn and put back. What is the probability that the sum of the two cards will be 8?
A. \(\frac{2}{3}\)
B. \(\frac{1}{2}\)
C. \(\frac{5}{12}\)
D. \(\frac{2}{5}\)
E. \(\frac{5}{36}\)
M37-107
A. \(\frac{2}{3}\)
B. \(\frac{1}{2}\)
C. \(\frac{5}{12}\)
D. \(\frac{2}{5}\)
E. \(\frac{5}{36}\)
M37-107
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05 Feb 2022, 04:00
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Bunuel
There are 6 cards numbered from 1 to 6. They are placed into a box, and then one is drawn and put back and then another card is drawn and put back. What is the probability that the sum of the two cards will be 8?
A. \(\frac{2}{3}\)
B. \(\frac{1}{2}\)
C. \(\frac{5}{12}\)
D. \(\frac{2}{5}\)
E. \(\frac{5}{36}\)
A. \(\frac{2}{3}\)
B. \(\frac{1}{2}\)
C. \(\frac{5}{12}\)
D. \(\frac{2}{5}\)
E. \(\frac{5}{36}\)
\(P(sum \ of \ 8) = \)
\( =P(5, 3) + P(3, 5) + P(6, 2) + P(2, 6) + P(4, 4) = \)
\( = \frac{1}{6}*\frac{1}{6} + \frac{1}{6}*\frac{1}{6} + \frac{1}{6}*\frac{1}{6} + \frac{1}{6}*\frac{1}{6} + \frac{1}{6}*\frac{1}{6} = \)
\( = \frac{5}{36}\).
Answer: E.
General Discussion
28 Jan 2022, 05:04
Kudos
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Bunuel
There are 6 cards numbered from 1 to 6. They are placed into a box, and then one is drawn and put back and then another card is drawn and put back. What is the probability that the sum of the two cards will be 8?
A. \(\frac{2}{3}\)
B. \(\frac{1}{2}\)
C. \(\frac{5}{12}\)
D. \(\frac{2}{5}\)
E. \(\frac{1}{15}\)
A. \(\frac{2}{3}\)
B. \(\frac{1}{2}\)
C. \(\frac{5}{12}\)
D. \(\frac{2}{5}\)
E. \(\frac{1}{15}\)
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