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Amby02
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Amby02
There are 8 different circles. What is the greatest number of the possible points that the circles intersect?

A. 48
B. 56
C. 64
D. 70
E. 80

Maximum point of Intersection between n different Circles. = 2 *nC2, where n >= 2.
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Given 2 identical circles (call them circle A and circle B) the MAX Intersection we can get with the 2 identical circles is ———> 2 points


The 3rd circle C: can get a maximum of 2 intersection points with circle A and a maximum of 2 intersection points with circle B ——-> + 4 more intersection points


The 4th circle D: can get a maximum of 2 intersection points with Each of the 3 prior circles ——> (2) (3) = + 6

5th circle: + 8 new points

6th circle: + 10 new points

7th circle: + 12 new points

8th circle: + 14 new points

Thus for 8 circles, the MAX intersection points we can get are:

(2) + (4) + (6) + (8) + (10) + (12) + (14) =

(7) * (8) =

56

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Amby02
There are 8 different circles. What is the greatest number of the possible points that the circles intersect?

A. 48
B. 56
C. 64
D. 70
E. 80

Total ways of chosing first circle = 8

Total no of ways of selecting the second point without coinciding with the chosen point =7

Therefore total way of unique chosing = 8*7 = 56

Therefore IMO B
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Bunuel did not understand the problem! :/
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