There are 8 marbles in a bag, 4 of them are red and others

Question

There are 8 marbles in a bag, 4 of them are red and others are white. If 3 marbles are randomly drawn out from the bag, what is the probability that at least one of the marbles is red?

gmat2me2 · Answer

Let the 3 things drawn out are white == 4C3 ways

Total no of ways of drawing are 8C3

So probabaility of drawing only white is 4C3/8C3 = 1/14

So probability of red being drawn = 1-1/14 = 13/14

amit_drummer · Answer

1 - Prob(Not picking any RED marble) OR Prob(Picking up all 3 WHITE marbles)

1 - 4C3/8C3

gmat2me2 · Answer

Can we use the bionomial method like

8C3(1/4)((1/4)^2) +.... kind??

sparky · Answer

13/14 =1- 4c3/8c3 (all white) = (4c1x4c2+4c2x4c1+4c3)/8c3 (at least one read)

rxs0005 · Answer

total ways 8C3 = 56 

Total ways 3 marbles are white = 4C3 = 4 

all white marbles or none red marbles = 4/56 = 1/14 

so At least one red = 1 - 1 / 14 = 13/14

WinWinMBA · Answer

The chance of at least one red = 1- P(all 3 are white)


 = 1- (4/8 x3/7 x2/6)
 
 = 1- 1/14 
 
 = 13/14

ashkg · Answer

P ( at least 1 red ) = 1 - P( no red )

Also , P ( no red ) = P ( all white ) = 4C3/8C3


Final ans = 1 -4C3/8C3 = 13/14

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There are 8 marbles in a bag, 4 of them are red and others

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