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17 Jan 2021, 09:24
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
68% (01:11) correct
32%
(01:23)
wrong
based on 100
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There are five computers in an office, out of which two are faulty. On a morning two computers are picked at random for testing, without replacement. What is the probability that they are both NOT faulty?
A. 1/10
B. 1/5
C. 3/10
D. 7/10
E. 9/10
A. 1/10
B. 1/5
C. 3/10
D. 7/10
E. 9/10
There are 5 computers in an office and two are faulty. On a morning two computers are picked at random for testing. What is the probability that they are both NOT faulty?
17 Jan 2021, 09:42
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Bunuel
\(Probability = \frac{Desired#ofOutcomes}{Possible#ofOutcomes}\)
There are 5C2 possible number of outcomes, \(5C2 = \frac{5*4}{2!} = 10\).
There are 3C2 desired outcomes, 3C2 = 3C1 = 3. Thus the probability is \(\frac{3}{10}\).
Ans: C
05 Feb 2021, 22:57
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Bunuel
Possible outcomes when taking two computers are:
\(✗✗ = \frac{2}{5}*\frac{1}{4} = \frac{1}{10}\)
\(✗✓ = \frac{2}{5}*\frac{3}{5} = \frac{6}{25}\)
\(✓✗ = \frac{3}{5}*\frac{2}{5} = \frac{6}{25}\)
\(✓✓ = \frac{3}{5}*\frac{2}{4} = \frac{3}{10}\)
The last one is what we need.
Answer C,
