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# There are m mangoes and c custardapples in a bowl. Carol ate

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Intern
Status: Learning
Joined: 07 Aug 2011
Posts: 36
Location: India
Schools: WBUT - Class of 2011
GMAT Date: 01-06-2014
GPA: 2.6
WE: Research (Education)
There are m mangoes and c custardapples in a bowl. Carol ate  [#permalink]

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Updated on: 12 May 2014, 01:29
5
00:00

Difficulty:

15% (low)

Question Stats:

84% (01:01) correct 16% (00:57) wrong based on 56 sessions

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There are m mangoes and c custardapples in a bowl. Carol ate 2 mangoes and 3 custardapples from the bowl. If Carol now picks up a fruit from the bowl at random, what is the probability that the fruit will be mango? [Given: m > 2 and c > 3 ]

A. m/(m+c)

B. (m-2)/(m+c)

C. (m-3)/(m+c-5)

D. (m-2)/(m+c+5)

E. (m-2)/(m+c-5)

Originally posted by arindamsur on 12 May 2014, 01:19.
Last edited by Bunuel on 12 May 2014, 01:29, edited 1 time in total.
Edited the options and added the OA.
Math Expert
Joined: 02 Sep 2009
Posts: 61190
Re: There are m mangoes and c custardapples in a bowl. Carol ate  [#permalink]

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12 May 2014, 01:31
arindamsur wrote:
There are m mangoes and c custardapples in a bowl. Carol ate 2 mangoes and 3 custardapples from the bowl. If Carol now picks up a fruit from the bowl at random, what is the probability that the fruit will be mango? [Given: m > 2 and c > 3 ]

A. m/(m+c)

B. (m-2)/(m+c)

C. (m-3)/(m+c-5)

D. (m-2)/(m+c+5)

E. (m-2)/(m+c-5)

After Carol ate 2 mangoes and 3 custardapples, there are m-2 mangoes and c-3 custardapples left in the bowl, so total (m-2)+(c-3) = m+n-5 fruits.

P = (favorable)/(total) = (m-2)/(m+c-5).

P.S. Please provide the OA's when posting and make sure the options are written correctly. Thank you.
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Re: There are m mangoes and c custardapples in a bowl. Carol ate   [#permalink] 12 May 2014, 01:31
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