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There are three consecutive #s such that the square of the middle # exceeds the difference of the squares of the first and last #s by 60. What is the last of the three #s?
10
14
11
17
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Kpadma, please note that the question is about the DIFFERENCE BETWEEN THE FIRST AND THE LAST NUMBER not the other way round.If you try the values that you have suggested you 'll see that 9,10,11 9^2-11^2=-40 so the square of the middle number exceeds the difference by 140, not 60. IMO, the numbers are -11,-10,-9 so the answer should be E)
Kpadma, please note that the question is about the DIFFERENCE BETWEEN THE FIRST AND THE LAST NUMBER not the other way round.
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Yes, you've a point. I've also noticed that issue, when I solved the problem.
But, Is it not true that the difference between two number is always postive
or zero. For exampble, "difference between A and B" is | A - B |, whereas
"A exceeds B" is A - B.
I could be wrong, so it is worth clearing up this confusion.
Dear Praetorian or Akamai,
Could you help us with this issue?
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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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