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Bunuel
There are two solutions, A and B of spirit and water. The ratio of spirit and water in solution A is 3:4 and 4:5 in solution B, if 28 litre of solution is taken from A and added to Solution B, what will be the final concentration of spirit in solution B.

(1) After the addition, water in solution B is 24 L more than spirit.

(2) Initial amount of solution A is 140 L
 

This question is a part of Are You Up For the Challenge: 700 Level Questions collection.­
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S : W
(A) 3: 4 = 3x and 4x
(B) 4 :5 = 4y and 5y
In those 28 ltrs also, the ratio of 3:4 will be intact. So, Sprit added is 12 ltr and water added is 16 ltr. therefore
Spirit in B = 4y + 12 Ltrs
Water in B = 5y + 16 Ltrs

Stt. 1, 5y + 16 = 4y + 12 + 24
hence sufficent

stt. B, no info about B volme or anything
Hence Stt. 1 is Suff.
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So, in that 28ltrs:
7x = 28; x = 4
12ltrs of spirit is there
16ltrs of water is there
In B, new concentration will be:
Spirit = x + 12
Water = x + 16
1)x + 12/x+16+24 = 4/5
Thus, x = 20
Sufficient to find final concentration.
2)Initial amount =140 L
But, we need to know either the entire volume of solution B or the relationship between volume of water and spirit in solution B- Insufficient!
Therefore, answer is A.

Bunuel
There are two solutions, A and B of spirit and water. The ratio of spirit and water in solution A is 3:4 and 4:5 in solution B, if 28 litre of solution is taken from A and added to Solution B, what will be the final concentration of spirit in solution B.

(1) After the addition, water in solution B is 24 L more than spirit.

(2) Initial amount of solution A is 140 L
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