Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 1212:00 PM EDT
-11:59 PM EDT
Make the most of your break with the most realistic GMAT™ prep. Take up to $700 off select products.
May 1308:30 AM PDT
-09:30 AM PDT
In Episode 4 of our GMAT Ninja CR series, we tackle the most intimidating CR question type: Boldface & "Legalese" questions. If you've ever stared at an answer choice that reads, "The first is a consideration introduced to counter a position that...- May 14
08:30 AM PDT
-09:30 AM PDT
Most GMAT test-takers are intimidated by the hardest GMAT Verbal questions. In this session, Target Test Prep GMAT instructor Erika Tyler-John, a 100th percentile GMAT scorer, will show you how top scorers break down challenging Verbal questions..
12 Aug 2020, 23:48
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
52% (02:10) correct
48%
(02:41)
wrong
based on 46
sessions
History
Date
Time
Result
Not Attempted Yet
There is a point P inside a regular hexagon such that area of \(\triangle\) PFA = 8 cm^2, area of \(\triangle\) PBC = 3 cm^2 and area of \(\triangle\) PDE = 5cm^2. Find the area of \(\triangle PCD\) (highlighted in green)?
A. 2 cm^2
B. \(\frac{8}{3}\) cm^2
C. 3 cm^2
D. \(\frac{11}{3}\) cm^2
E. 4 cm^2
A. 2 cm^2
B. \(\frac{8}{3}\) cm^2
C. 3 cm^2
D. \(\frac{11}{3}\) cm^2
E. 4 cm^2
Attachments
Untitled.png [ 7.54 KiB | Viewed 4829 times ]
yashikaaggarwal
Senior Moderator - Masters Forum
Joined: 19 Jan 2020
Last visit: 29 Mar 2026
Posts: 3,087
Given Kudos: 1,510
Location: India
Schools: Cranfield (A) Warwick MiM "23 (M)
GPA: 4
WE:Analyst (Internet and New Media)
15 Aug 2020, 09:54
Kudos
Bookmarks
15 Aug 2020, 10:51
Kudos
Bookmarks
yashikaaggarwal
An immediate answer.
The opposite sides are parallel and distance between each set of parallel sides will be equal.
The height from P to each opposite parallel side would add up to H.
Note- On mobile, so will add a detailed explanation and sketch.
But the hexagon can be divided into equal areas by adding the areas of alternate triangles.
PAB+PCD+PEF=PBC+PDE+PFA=8+5+3=16
So total area =16*2=32.
Now the opposite triangles should add up to 1/3 of total area as there are 3 sets of opposite triangle whose heights add up to same H and also the base is same.
So each set of opposite triangles will have an area 32/3.
So area of highlighted triangle = 32/3-8=8/3
B
