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24 Jan 2006, 14:42
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This is a problem I received in my email from Princeton review! They claim that if you can solve this DS you are propably ready to take the GMAT, and that questions like this appear on the actual exam...I saw the solution and it is about one page! It takes more than 10 minutes to solve such an exercise. Do you agree that we may see questions that require so many calculations on the gmat? Is there a shorter solution?
link with DS problem and solution:
https://www.princetonreview.com/mba/testprep/testprep.asp?tprpage=838&TYPE=GMAT-TOOLS&adcode=26307
link with DS problem and solution:
https://www.princetonreview.com/mba/testprep/testprep.asp?tprpage=838&TYPE=GMAT-TOOLS&adcode=26307
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24 Jan 2006, 16:29
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first of all I have to admit I took way long to solve this question and I still got the wrong answer. Then thinking about it, none of these questions ask you to solve the answer... they just ask you if the information you have is sufficient. The following hinders on 1 assumption as you'll see. I'm not claiming i'm correct but rather i'm asking the community if it makes sense.
BD= v
DA= y
BC =1
DC=x
CA=z
we want to know if x+y+z=5 (perimeter). we can solve for z using the PT (pythag theorem). Thus x+y+f(xy)=5 where f(xy) is some function of xy that equals z.
statement 1 tells us .5*xv=4*.5xy or xv=4xy. We already know that x^2 +v^2 =1 (PT) so we can solve for x in terms of v and substitute it in the first equation and get x*f(x)=4xy where f(x) is some function of x that equals v. We basically have 2 equations with 2 variables now. this should be enough in formation to solve the question.
statement 2 tells us that y=2x. same principle as statement 1 where you have 2 equations and 2 variables.
thoughts? to solve the problem incorrectly it took me 10mins at least. It took me 2 minutes to deduce this logic. then again I might be wrong :/
BD= v
DA= y
BC =1
DC=x
CA=z
we want to know if x+y+z=5 (perimeter). we can solve for z using the PT (pythag theorem). Thus x+y+f(xy)=5 where f(xy) is some function of xy that equals z.
statement 1 tells us .5*xv=4*.5xy or xv=4xy. We already know that x^2 +v^2 =1 (PT) so we can solve for x in terms of v and substitute it in the first equation and get x*f(x)=4xy where f(x) is some function of x that equals v. We basically have 2 equations with 2 variables now. this should be enough in formation to solve the question.
statement 2 tells us that y=2x. same principle as statement 1 where you have 2 equations and 2 variables.
thoughts? to solve the problem incorrectly it took me 10mins at least. It took me 2 minutes to deduce this logic. then again I might be wrong :/
24 Jan 2006, 17:41
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Even though I solved it in 5-6 minutes using similar triangles but I don't think we gonna face these problems on real GMAT. If you are, then its almost certain you scored 50-51 in quant. 
