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This stem-and-leaf plot shows the number of automobiles sold by 22 sal

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This stem-and-leaf plot shows the number of automobiles sold by 22 sal  [#permalink]

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New post 12 Feb 2019, 01:20
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This stem-and-leaf plot shows the number of automobiles sold by 22 sales associates of a Ace Auto Sales during the month of January. Next month, management wants to increase its average number of automobiles sold per salesperson to 35. If the number of sales associates remains at 22, on average how many additional automobiles will each salesperson need to sell next month for management to reach this goal?
Image

(A) 3
(B) 5
(C) 32
(D) 35
(E) 110

Attachment:
2019-02-12_1218.png
2019-02-12_1218.png [ 32.7 KiB | Viewed 448 times ]

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This stem-and-leaf plot shows the number of automobiles sold by 22 sal  [#permalink]

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New post Updated on: 12 Feb 2019, 21:06
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Sum of total number of automobiles sold = 660

\(\frac{660+x}{22} = 35\)
\(x=110\)
Total additional automobiles needed to be sold = 110
Additional automobiles per sales associate = 110/22 = 5

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Kudos if helpful!

Originally posted by GMATMBA5 on 12 Feb 2019, 02:23.
Last edited by GMATMBA5 on 12 Feb 2019, 21:06, edited 1 time in total.
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Re: This stem-and-leaf plot shows the number of automobiles sold by 22 sal  [#permalink]

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New post 12 Feb 2019, 03:12
Can someone explain it in a detailed manner.

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This stem-and-leaf plot shows the number of automobiles sold by 22 sal  [#permalink]

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New post 12 Feb 2019, 03:21
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Poorvi55 wrote:
Can someone explain it in a detailed manner.

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From the stem-and-leaf plot, we have below number of automobiles sold by 22 sales associates.
12 15 17 18 18
22 23 23 24 25 25 25
32 34 34 34 38 39 39
50 52
61

First column in the stem-and-leaf plot is the stem and second column is the leaf. Stem forms the first digit of the number and leaf forms the second digit.
Adding all numbers above we get, 660 automobiles sold by 22 sales associates.
average = 660/22 = 30

Now it is asked that for how many additional automobiles sold by the same 22 associates the average will be 35. So let x be the additional automobiles,
\(\frac{660+x}{22}=35\)
\(x=110\)

Therefore, additional automobiles per sales associate = 110/22 = 5

The method followed by me is a lengthy one. Any shortcut method is appreciated.

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This stem-and-leaf plot shows the number of automobiles sold by 22 sal   [#permalink] 12 Feb 2019, 03:21
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This stem-and-leaf plot shows the number of automobiles sold by 22 sal

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