Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1511:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.
Dec 1410:00 AM EST
-12:00 PM EST
Think a 100% GMAT Verbal score is out of your reach? Target Test Prep will make you think again! Our course uses techniques such as topical study and spaced repetition to maximize knowledge retention and make studying simple and fun.- Dec 14
11:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test. 
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!- Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options.
15 Oct 2019, 02:34
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
97% (01:32) correct
3%
(01:43)
wrong
based on 31
sessions
History
Date
Time
Result
Not Attempted Yet
Three brothers – Maurice, Larry and Curly – bought their parents an anniversary gift that cost $180. How much did Curly contribute to the purchase price?
(1) Maurice paid twice as much as the average (arithmetic mean) contributed by all three brothers.
(2) Larry paid one-third of the average amount contributed by his brothers.
(1) Maurice paid twice as much as the average (arithmetic mean) contributed by all three brothers.
(2) Larry paid one-third of the average amount contributed by his brothers.
Updated on: 15 Oct 2019, 05:43
Originally posted by CareerGeek on 15 Oct 2019, 04:07.
Last edited by CareerGeek on 15 Oct 2019, 05:43, edited 1 time in total.
Last edited by CareerGeek on 15 Oct 2019, 05:43, edited 1 time in total.
Kudos
Bookmarks
Bunuel
Three brothers – Maurice, Larry and Curly – bought their parents an anniversary gift that cost $180. How much did Curly contribute to the purchase price?
(1) Maurice paid twice as much as the average (arithmetic mean) contributed by all three brothers.
(2) Larry paid one-third of the average amount contributed by his brothers.
(1) Maurice paid twice as much as the average (arithmetic mean) contributed by all three brothers.
(2) Larry paid one-third of the average amount contributed by his brothers.
Let the contributions of Maurice, Larry and Curly be M, L & C respectively
--> M + L + C = 180
(1) Maurice paid twice as much as the average (arithmetic mean) contributed by all three brothers.
\(M = 2\frac{(M + L + C)}{3} = 2*\frac{180}{3} = 120\)
--> M = 120
--> 120 + L + C = 180
--> L + C = 60
Many values of C are possible --> Insufficient
(2) Larry paid one-third of the average amount contributed by his brothers.
\(L = \frac{1}{3}*\frac{(M + C)}{2}\)
--> 6L = M + C
--> 6L + L = M + L + C
--> 7L = 180
--> L = 180/7
--> M + C = 1080/7
Many values of C are possible --> Insufficient
Combining (1) & (2),
M = 120, L = 180/7
We can find definite value of C --> Sufficient
IMO Option C
15 Oct 2019, 04:32
Kudos
Bookmarks
Bunuel
Three brothers – Maurice, Larry and Curly – bought their parents an anniversary gift that cost $180. How much did Curly contribute to the purchase price?
(1) Maurice paid twice as much as the average (arithmetic mean) contributed by all three brothers.
(2) Larry paid one-third of the average amount contributed by his brothers.
(1) Maurice paid twice as much as the average (arithmetic mean) contributed by all three brothers.
(2) Larry paid one-third of the average amount contributed by his brothers.
From the question stem, \(M + L + C = 180\). We are asked the value of C
1. \(\frac{M}{2} = \frac{M + L + C}{3}\) -> \(M = 2(L + C)\)
We cannot determine a unique value for M,L, or C. (Insufficient)
2. \(3L = \frac{M + C}{2}\) -> \(6L = M + C\) -> \(M = 6L - C\)
We cannot determine a unique value for M,L, or C. (Insufficient)
On combining the information in both the statements, we will get
\(6L - C = 2(L + C)\) -> \(4L - 3C = 0\) -> \(4L = 3C\)
\(M = 2L + 2C\) -> \(2M = 4L + 4C\) -> \(M = 7C\) AND \(6L = 8C\)
Therefore, with this information, we can find an unique value of C (Sufficient - Option C)
