DeeptiM
Three interviewers, A, B, and C are interviewing 40 applicants. Only with three interviewers' admission can an applicant be admitted. If interviewer A admitted 15 applicants, B admitted 17 applicants, and C admitted 20 applicants, at least how many applicants get the admission?
(A) 0
(B) 2
(C) 6
(D) 8
(E) 12
GIVEN: - Total number of applicants = 40
- Interviewers A, B, and C selected 15, 17, and 20 applicants, respectively.
- An applicant gets admitted only when he is selected by ALL three interviewers.
TO FIND: - Minimum number of applicants to get admission.
- That is, the minimum number of applicants who are selected by all three interviewers.
SOLUTION: We will solve this question in some neatly laid out steps. Just follow each section and make sure you understand every bit of the solution. Let’s go!
Define variables: Let’s assign some variables first that will denote the various possibilities of selection:
- Selected by ALL three:
- Say w = number of applicants selected by all three interviewers
- Selected by EXACTLY two:
- x = the number of applicants selected by only A and B.
- Y = the number of applicants selected by only A and C.
- z = the number of applicants selected by only B and C.
- Selected by NONE:
- N = the number of applicants selected by none of the three interviewers.
Note: Since nothing has been said about each applicant being selected by at least one interviewer, there is a possibility that some of the applicants are selected by none of the interviewers.
Represent on Venn diagram: Now, we’ll draw a Venn diagram that will clearly show the scenario at play here. We will use the variables as we defined above. Here goes:

Despite populating all we know, there still are some empty regions in our Venn diagram. But it’s no big deal. Using what the diagram already has, we can easily find the values of the empty regions as well. It’s always a good idea to understand all possible regions!
So, here’s what we can infer:
- Number of applicants selected by only A = 15 – x – y – w. (This is the part of circle A that does not meet any other circle.)
- Number of applicants selected by only B = 17 – x – z – w. (This is the part of circle A that does not meet any other circle.)
- Number of applicants selected by only C = 20 – y – z – w. (This is the part of circle A that does not meet any other circle.)
And done! Now, it’s time for the main question asked – the minimum possible value of ‘w’.
Finding Minimum possible ‘w’: Looking at the Venn diagram, we can say that:
Total applicants = Selected by
only A + Selected by
only B + Selected by
only C + Selected by
only A and B + Selected by
only A and C + Selected by
only B and C + Selected by
all A, B and C + Selected by
None ----(I)
Rewriting the equation using all our variables, we get:
- 40 = (15 – x – y – w) + (17 – x – z – w) + (20 – y – z – w) + x + y + z + w + N
⇒ 40 = 52 – 2w – x – y – z + N
⇒ 2w = 12 - (x + y + z) + N ----(II)
Observe that to minimize ‘w’, we need to
maximize (x + y + z) and minimize (N). Why?
- Because the larger a value we subtract from 12, the smaller the remaining difference will be, leading to a smaller ‘w’.
- And the smaller a value we add to 12, the smaller the resulting sum will be, leading to a smaller ‘w’.
PART 1: Minimize N At the least, N can take a minimum value of
ZERO. This is when each of the 40 applicants were selected by at least one of the three interviewers.
In this case, (II) becomes:
- 2w = 12 - (x + y + z) ----(III)
PART 2: Maximize (x + y + z) Note that ‘w’, being a certain number of applicants, cannot be negative. Hence, the maximum that we can subtract from 12 is 12 itself. That is maximum (x + y + z) = 12.
Hence, from (III), we get 2w = 12 – 12 = 0.
This implies that the
minimum possible value for w is
ZERO.
Correct Answer: Option A Hope this helps!
Best,
Aditi Gupta
Quant expert,
e-GMAT