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Three thousand families live in a certain town. How many families who

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Bunuel
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Three thousand families live in a certain town. How many families who [#permalink] New post  16 Oct 2019, 07:21
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Three thousand families live in a certain town. How many families who live in the town own neither a car nor a television set?

(1) Of the families who live in the town, 2,980 own a car.

(2) Of the families who live in the town, 2,970 own both a car and a television set.
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TarunTilokani
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Re: Three thousand families live in a certain town. How many families who [#permalink] New post  21 Oct 2019, 23:01
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The answer would be E
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Archit3110
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Three thousand families live in a certain town. How many families who [#permalink] New post  Updated on: 17 Oct 2019, 05:05
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Bunuel wrote:
Three thousand families live in a certain town. How many families who live in the town own neither a car nor a television set?

(1) Of the families who live in the town, 2,980 own a car.

(2) Of the families who live in the town, 2,970 own both a car and a television set.


solve using 2x2
we get
---tv--- ntv----total
car--2970--10---2980
nc--- 10/20------ 10/0---20
total 2980----20----3000

the column of ntv and nc can be 10 or 0
IMO E

Originally posted by Archit3110 on 16 Oct 2019, 07:28.
Last edited by Archit3110 on 17 Oct 2019, 05:05, edited 1 time in total.
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Shorub
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Re: Three thousand families live in a certain town. How many families who [#permalink] New post  16 Oct 2019, 08:03
Archit3110

How did u assume the total number of families in the town?

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lacktutor
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Re: Three thousand families live in a certain town. How many families who [#permalink] New post  16 Oct 2019, 09:33
Archit3110 wrote:
Bunuel wrote:
Three thousand families live in a certain town. How many families who live in the town own neither a car nor a television set?

(1) Of the families who live in the town, 2,980 own a car.

(2) Of the families who live in the town, 2,970 own both a car and a television set.


solve using 2x2
we get
---tv--- ntv----total
car--2970--10---2980
nc--- 10------ 10---20
total 2980----20----3000
IMO C


Hi,
How did you get the total number of Tv.set which is equal to 2980?

Thanks in advance.

Posted from my mobile device
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Archit3110
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Three thousand families live in a certain town. How many families who [#permalink] New post  Updated on: 17 Oct 2019, 05:06
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Shorub its given 3000 families live in a certain town

lacktutor

i solved quesiton using 2x2 matrix if you see #1
Of the families who live in the town, 2,980 own a car.
we get
---tv--- no tv----total
car-- --- --2980
no car--- ------ ---
total ----]----3000
insufficient

#2
Of the families who live in the town, 2,970 own both a car and a television set
---tv--- no tv----total
car-- 2970--- --2970
no car--- ------ --- 30
total ---- ----3000
again insufficient
from 1&2
---tv--- no tv----total
car--2970--10---2980
no car--- 10/20------ 10/0---20
total 2980----20/10----3000
sufficient
IMO E ; 20 /0 r

lacktutor wrote:
Archit3110 wrote:
Bunuel wrote:
Three thousand families live in a certain town. How many families who live in the town own neither a car nor a television set?

(1) Of the families who live in the town, 2,980 own a car.

(2) Of the families who live in the town, 2,970 own both a car and a television set.


solve using 2x2
we get
---tv--- ntv----total
car--2970--10---2980
nc--- 10------ 10---20
total 2980----20----3000
IMO C


Hi,
How did you get the total number of Tv.set which is equal to 2980?

Thanks in advance.

Posted from my mobile device

Originally posted by Archit3110 on 16 Oct 2019, 10:29.
Last edited by Archit3110 on 17 Oct 2019, 05:06, edited 1 time in total.
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Shorub
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Re: Three thousand families live in a certain town. How many families who [#permalink] New post  16 Oct 2019, 10:31
Archit3110

My mistake. Did not notice. Thanks.

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gvij2017
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Re: Three thousand families live in a certain town. How many families who [#permalink] New post  16 Oct 2019, 16:05
Total= A+B-Both A&B+Neither A nor B.

Given: Total: 3000
We have to calculate =Neither A nor B.

Statement1
All having car, few of them might have TV =A= 2980.
Not sufficient.

Statement: 2
Both having car and TV= A&B: 2970.

Statement 1+2
3000= 2980+B-2970+Neither A nor B.
Neither A nor B +B= 20
Now we don't know the value of B.

Not sufficient.
E is answer.
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SPatel1992
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Re: Three thousand families live in a certain town. How many families who [#permalink] New post  16 Oct 2019, 17:02
Archit3110 wrote:
Bunuel wrote:
Three thousand families live in a certain town. How many families who live in the town own neither a car nor a television set?

(1) Of the families who live in the town, 2,980 own a car.

(2) Of the families who live in the town, 2,970 own both a car and a television set.


solve using 2x2
we get
---tv--- ntv----total
car--2970--10---2980
nc--- 10------ 10---20
total 2980----20----3000
IMO C



Why did you split 20 equally? What 0 families did not have a car and 20 families did not have a tv or vice versa?
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BLTN
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Re: Three thousand families live in a certain town. How many families who [#permalink] New post  18 Oct 2022, 05:48
SPatel1992 wrote:
Archit3110 wrote:
Bunuel wrote:
Three thousand families live in a certain town. How many families who live in the town own neither a car nor a television set?

(1) Of the families who live in the town, 2,980 own a car.

(2) Of the families who live in the town, 2,970 own both a car and a television set.


solve using 2x2
we get
---tv--- ntv----total
car--2970--10---2980
nc--- 10------ 10---20
total 2980----20----3000
IMO C



Why did you split 20 equally? What 0 families did not have a car and 20 families did not have a tv or vice versa?



I presume there is a typo; we do not have info to fill the No-Car row.
Furthermore, we do not have total # of TV also.

What we have is that
Total = Cars +TV - Both + Neither
3000 = 2980 + TV - 2970 + Neither
2990 = TV + Neither
Neither = 2990 - TV; insufficient because we do not have # of TV
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Re: Three thousand families live in a certain town. How many families who [#permalink]
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