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Bunuel
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Three thousand families live in a certain town. How many families who 16 Oct 2019, 08:21
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E
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5% (low)

Question Stats:

88% (01:16) correct 12% (01:08) wrong based on 389 sessions

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Three thousand families live in a certain town. How many families who live in the town own neither a car nor a television set?

(1) Of the families who live in the town, 2,980 own a car.

(2) Of the families who live in the town, 2,970 own both a car and a television set.
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E
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Three thousand families live in a certain town. How many families who 22 Oct 2019, 00:01
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The answer would be E
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Three thousand families live in a certain town. How many families who Updated on: 17 Oct 2019, 06:05
Originally posted by Archit3110 on 16 Oct 2019, 08:28.
Last edited by Archit3110 on 17 Oct 2019, 06:05, edited 1 time in total.
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Bunuel
Three thousand families live in a certain town. How many families who live in the town own neither a car nor a television set?

(1) Of the families who live in the town, 2,980 own a car.

(2) Of the families who live in the town, 2,970 own both a car and a television set.
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solve using 2x2
we get
---tv--- ntv----total
car--2970--10---2980
nc--- 10/20------ 10/0---20
total 2980----20----3000

the column of ntv and nc can be 10 or 0
IMO E
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Three thousand families live in a certain town. How many families who 16 Oct 2019, 09:03
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Archit3110

How did u assume the total number of families in the town?

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Three thousand families live in a certain town. How many families who 16 Oct 2019, 10:33
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Archit3110
Bunuel
Three thousand families live in a certain town. How many families who live in the town own neither a car nor a television set?

(1) Of the families who live in the town, 2,980 own a car.

(2) Of the families who live in the town, 2,970 own both a car and a television set.

solve using 2x2
we get
---tv--- ntv----total
car--2970--10---2980
nc--- 10------ 10---20
total 2980----20----3000
IMO C
Show more

Hi,
How did you get the total number of Tv.set which is equal to 2980?

Thanks in advance.

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Three thousand families live in a certain town. How many families who Updated on: 17 Oct 2019, 06:06
Originally posted by Archit3110 on 16 Oct 2019, 11:29.
Last edited by Archit3110 on 17 Oct 2019, 06:06, edited 1 time in total.
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Shorub its given 3000 families live in a certain town

lacktutor

i solved quesiton using 2x2 matrix if you see #1
Of the families who live in the town, 2,980 own a car.
we get
---tv--- no tv----total
car-- --- --2980
no car--- ------ ---
total ----]----3000
insufficient

#2
Of the families who live in the town, 2,970 own both a car and a television set
---tv--- no tv----total
car-- 2970--- --2970
no car--- ------ --- 30
total ---- ----3000
again insufficient
from 1&2
---tv--- no tv----total
car--2970--10---2980
no car--- 10/20------ 10/0---20
total 2980----20/10----3000
sufficient
IMO E ; 20 /0 r

lacktutor
Archit3110
Bunuel
Three thousand families live in a certain town. How many families who live in the town own neither a car nor a television set?

(1) Of the families who live in the town, 2,980 own a car.

(2) Of the families who live in the town, 2,970 own both a car and a television set.

solve using 2x2
we get
---tv--- ntv----total
car--2970--10---2980
nc--- 10------ 10---20
total 2980----20----3000
IMO C

Hi,
How did you get the total number of Tv.set which is equal to 2980?

Thanks in advance.

Posted from my mobile device
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Three thousand families live in a certain town. How many families who 16 Oct 2019, 11:31
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Archit3110

My mistake. Did not notice. Thanks.

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Three thousand families live in a certain town. How many families who 16 Oct 2019, 17:05
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Total= A+B-Both A&B+Neither A nor B.

Given: Total: 3000
We have to calculate =Neither A nor B.

Statement1
All having car, few of them might have TV =A= 2980.
Not sufficient.

Statement: 2
Both having car and TV= A&B: 2970.

Statement 1+2
3000= 2980+B-2970+Neither A nor B.
Neither A nor B +B= 20
Now we don't know the value of B.

Not sufficient.
E is answer.
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Three thousand families live in a certain town. How many families who 16 Oct 2019, 18:02
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Archit3110
Bunuel
Three thousand families live in a certain town. How many families who live in the town own neither a car nor a television set?

(1) Of the families who live in the town, 2,980 own a car.

(2) Of the families who live in the town, 2,970 own both a car and a television set.

solve using 2x2
we get
---tv--- ntv----total
car--2970--10---2980
nc--- 10------ 10---20
total 2980----20----3000
IMO C
Show more


Why did you split 20 equally? What 0 families did not have a car and 20 families did not have a tv or vice versa?
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Three thousand families live in a certain town. How many families who 18 Oct 2022, 06:48
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SPatel1992
Archit3110
Bunuel
Three thousand families live in a certain town. How many families who live in the town own neither a car nor a television set?

(1) Of the families who live in the town, 2,980 own a car.

(2) Of the families who live in the town, 2,970 own both a car and a television set.

solve using 2x2
we get
---tv--- ntv----total
car--2970--10---2980
nc--- 10------ 10---20
total 2980----20----3000
IMO C


Why did you split 20 equally? What 0 families did not have a car and 20 families did not have a tv or vice versa?
Show more


I presume there is a typo; we do not have info to fill the No-Car row.
Furthermore, we do not have total # of TV also.

What we have is that
Total = Cars +TV - Both + Neither
3000 = 2980 + TV - 2970 + Neither
2990 = TV + Neither
Neither = 2990 - TV; insufficient because we do not have # of TV
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