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# Tim traveled 40 percent of the distance of his trip alone, continued a

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Math Expert
Joined: 02 Sep 2009
Posts: 51280
Tim traveled 40 percent of the distance of his trip alone, continued a  [#permalink]

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07 Jan 2015, 06:43
00:00

Difficulty:

5% (low)

Question Stats:

93% (01:13) correct 7% (02:07) wrong based on 70 sessions

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Tough and Tricky questions: Word Problems.

Tim traveled 40 percent of the distance of his trip alone, continued another 20 miles with Sam and then finished the last half of the trip alone. How many miles long was the trip?

A. 240
B. 200
C. 160
D. 100
E. 50

Kudos for a correct solution.

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Re: Tim traveled 40 percent of the distance of his trip alone, continued a  [#permalink]

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07 Jan 2015, 06:50
Bunuel wrote:

Tough and Tricky questions: Word Problems.

Tim traveled 40 percent of the distance of his trip alone, continued another 20 miles with Sam and then finished the last half of the trip alone. How many miles long was the trip?

A. 240
B. 200
C. 160
D. 100
E. 50

Kudos for a correct solution.

Let x be the total distance.

40% of x= 0.4x and 50% of x= 0.5x

then total will be,

= 0.4x+20+0.5x=x
->20=x- 0.9x
-> 20=0.1x---> Dividing both side by 0.1

We get x=200. So the answer is B.
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Posts: 275
Re: Tim traveled 40 percent of the distance of his trip alone, continued a  [#permalink]

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07 Jan 2015, 07:13
Bunuel wrote:

Tough and Tricky questions: Word Problems.

Tim traveled 40 percent of the distance of his trip alone, continued another 20 miles with Sam and then finished the last half of the trip alone. How many miles long was the trip?

A. 240
B. 200
C. 160
D. 100
E. 50

Kudos for a correct solution.

let total distance be x. thus we have,

20 miles = 10% of x
or x= 200 miles
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Re: Tim traveled 40 percent of the distance of his trip alone, continued a  [#permalink]

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07 Jan 2015, 08:49
Let X be the total distance

X - 0.4X - 0.5x = 20

0.1X = 20

X = 200

Option B.
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Joined: 29 Jan 2014
Posts: 1
Re: Tim traveled 40 percent of the distance of his trip alone, continued a  [#permalink]

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07 Jan 2015, 10:12
Let total distance be x. So equation will be
0.4x(alone) + 20(with Sam) + 0.5x(alone) = x
0.9x + 20 = x
0.1x = 20
x = 200

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Joined: 21 Aug 2010
Posts: 174
Location: United States
GMAT 1: 700 Q49 V35
Re: Tim traveled 40 percent of the distance of his trip alone, continued a  [#permalink]

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07 Jan 2015, 10:20
Bunuel wrote:

Tough and Tricky questions: Word Problems.

Tim traveled 40 percent of the distance of his trip alone, continued another 20 miles with Sam and then finished the last half of the trip alone. How many miles long was the trip?

A. 240
B. 200
C. 160
D. 100
E. 50

Kudos for a correct solution.

Tim traveled 10% of the travel with sam which is 20Miles

then total travel distance = 10*20 = 200miles

Ans B
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Re: Tim traveled 40 percent of the distance of his trip alone, continued a  [#permalink]

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07 Jan 2015, 10:28
First 40% Alone, last 50% alone
so 20 miles represents 10%
and complete trip represents 200miles
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Re: Tim traveled 40 percent of the distance of his trip alone, continued a  [#permalink]

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07 Jan 2015, 23:49

50% + 40% = 90% of the trip "x", Tim has travelled alone

So, rest 10% of the trip = 20 = has been travelled with Sam

So, $$\frac{10x}{100} = 20$$

x = 200
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Posts: 51280
Re: Tim traveled 40 percent of the distance of his trip alone, continued a  [#permalink]

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09 Jan 2015, 05:59
Bunuel wrote:

Tough and Tricky questions: Word Problems.

Tim traveled 40 percent of the distance of his trip alone, continued another 20 miles with Sam and then finished the last half of the trip alone. How many miles long was the trip?

A. 240
B. 200
C. 160
D. 100
E. 50

Kudos for a correct solution.

OFFICIAL SOLUTION:

(B) The easiest way to visualize this problem is to turn it into an equation. Let x be the total length of the trip. We then know that this is what Tim traveled: 0.4x (first part of the trip traveled alone) + 20 (miles traveled with Sam) + 0.5x (last leg of the trip traveled alone). Thus, 0.4x + 20 + 0.5x = x. Now solve for x:

0.4x + 20 + 0.5x = x
0.9x + 20 = x
20 = 0.1x
200 = x.

The total length of the trip was 200 miles. The answer is (B).
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Re: Tim traveled 40 percent of the distance of his trip alone, continued a  [#permalink]

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31 Jul 2018, 02:12
If 40% of the trip plus 20 miles of the trip yields the 50% of the total trip, then we can say that 20milies of the trip equals 10% of the total trip. 100% will be 200 miles.
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Re: Tim traveled 40 percent of the distance of his trip alone, continued a &nbs [#permalink] 31 Jul 2018, 02:12
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