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Kimberly77
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Bunuel
Tina and Rebecca had the same number of candies. Tina gave Rebecca 24 candies so that now Rebecca has five times as many candies as Tina has. Rebecca has now how many candies?

A. 36
B. 48
C. 54
D. 55
E. 60

Let x = the number of candies Tina ORIGINALLY had
So x = the number of candies Rebecca ORIGINALLY had

Tina gave Rebecca 24 candies so that now Rebecca has five times as many candies as Tina has.
x - 24 = the number of candies Tina has NOW
x + 24 = the number of candies Rebecca has NOW

We can write: x +24 = 5(x - 24)
Expand: x +24 = 5x - 120
Subtract x from both sides of the equation: 24 = 4x - 120
Add 120 to both sides of the equation: 144 = 4x
Divide both sides by 4 to get: x = 36

Important: x = the number of candies each person ORIGINALLY had, and x + 24 = the number of candies Rebecca has NOW

Since x = 36, we get x + 24 = 36 + 24 = 60
So Rebecca NOW has 60 candies

Hi BrentGMATPrepNow, can this be solved with using 2 variables as below? Thanks Brent

5 (T-24) = R + 24

I'm assuming:
T = the number of candies Tina had BEFORE the exchange.
R = the number of candies Rebecca had BEFORE the exchange.

In this case, you're right to conclude that 5 (T - 24) = R + 24
The only problem is that you have 1 equation with 2 variables, which means you can't solve it.

However, if we use the given information, Tina and Rebecca had the same number of candies., you can conclude that T = R, which means you now have 2 equations with 2 variables:
5 (T - 24) = R + 24
T = R
And this system CAN be solve.
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Fantastic, thanks BrentGMATPrepNow
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