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15 Jul 2019, 04:26
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A water tank has three taps A, B, and C. A fills four buckets in 24 mins, B fills 8 buckets in 1 hour and C fills 2 buckets in 20 minutes. If all the taps are opened together a full tank is emptied in 2 hours. If a bucket can hold 5 litres of water, what is the capacity of the tank in litres?
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Since a bucket holds 5 litres of water, Tap A discharges 20 litres of water in 24 minutes or 5/6 litres of water in 1 minute.
Tap B discharges 40 litres in 1 hours or 2/3 litres in 1 minute.
Tap C discharges 10 litres in 20 minutes or 1/2 litres in 1 minute.
If A, B & C are all opened simultaneously, total discharge = (5/6 + 2/3 + 1/2) = 2 litres in 1 minute.
So in 2 hours after all taps are opened, the discharge would be 240 litres, which should be the capacity of the tank.
Tap B discharges 40 litres in 1 hours or 2/3 litres in 1 minute.
Tap C discharges 10 litres in 20 minutes or 1/2 litres in 1 minute.
If A, B & C are all opened simultaneously, total discharge = (5/6 + 2/3 + 1/2) = 2 litres in 1 minute.
So in 2 hours after all taps are opened, the discharge would be 240 litres, which should be the capacity of the tank.
15 Jul 2019, 04:44
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Tap “A” 4 /24. ->10 /60 or 10 buckets / hr
Tap “B” 8 / 60 or 8 buckets / hr
Tap “C” 2/20 => 6/60 or 6 bucket / hr
Open together for 2 hrs and then tank is empty
So A+B+C = 24 buckets per hrs and 2 hrs -> 48 buckets.
One bucket is 5 L
Tank volume = 48 x 5 =240 L
Posted from my mobile device
Tap “B” 8 / 60 or 8 buckets / hr
Tap “C” 2/20 => 6/60 or 6 bucket / hr
Open together for 2 hrs and then tank is empty
So A+B+C = 24 buckets per hrs and 2 hrs -> 48 buckets.
One bucket is 5 L
Tank volume = 48 x 5 =240 L
Posted from my mobile device
