Let rate of tap I be x and rate of tap II be y
W=RT
2/3 = x*5
x=2/15
Together they did 1/3 of the work
1/3 = (2/15+y) *2
y = 1/6-2/15 = 1/30
Time taken by tap II alone to empty the full tank is 30hrs
Bunuel
To clean the water tank each tap in a house was kept open for some time. There were 2 taps in the houses numbered I and II with different draining capacities. Initially tap I was opened alone and could empty 2/3 of the tank in 5 hours. After that both the taps were opened together and the remaining tank could empty taking 2 more hours. How much time will the tap II alone take to empty the full tank?
(A) 8 hours
(B) 10 hours
(C) 15 hours
(D) 20 hours
(E) 30 hours
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