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25 Mar 2024, 01:30
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
81% (01:01) correct
19%
(01:29)
wrong
based on 121
sessions
History
Date
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Not Attempted Yet
To fill a number of vacancies, an employer must hire 3 programmers from among 6 applicants and 2 managers from among 4 applicants. What is the total number of ways in which she can make her selection?
(A) 1,490
(B) 132
(C) 120
(D) 60
(E) 23
(A) 1,490
(B) 132
(C) 120
(D) 60
(E) 23
25 Mar 2024, 03:05
Kudos
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Feel free to correct me, for the programmers it’s 6C3, which equals 20, and for the managers its 4C2 which equals 6, 6 multiplied by 20 =120, so C
25 Mar 2024, 08:23
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The answer will be: (the number of ways to choose 3 programmers from 6 applicants)*(the number of ways to choose 2 managers from 4 applicants)
The number of ways to choose 3 programmers from 6 applicants: \(\frac{6!}{3!3!} = 20\)
The number of ways to choose 2 managers from 4 applicants: \(\frac{4!}{2!2!} = 6\)
Plugging these values back into the initial equation: \(20*6 = 120\)
Answer C
The number of ways to choose 3 programmers from 6 applicants: \(\frac{6!}{3!3!} = 20\)
The number of ways to choose 2 managers from 4 applicants: \(\frac{4!}{2!2!} = 6\)
Plugging these values back into the initial equation: \(20*6 = 120\)
Answer C
