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30 Jun 2012, 23:45
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B
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Difficulty:
95%
(hard)
Question Stats:
44% (02:24) correct
56%
(02:16)
wrong
based on 279
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A man sets out to cycle from BBSR to CTC and at the same time another man starts from CTC to BBSR. After passing each other they complete their journeys in 4 and 9 hrs respectively. At what rate does the second man cycle if the first one cycles at 9 km/hr.
A. 4 km/hr
B. 6 km/hr
C. 8 km/hr
D. 9 km/hr
E. can't be determined
A. 4 km/hr
B. 6 km/hr
C. 8 km/hr
D. 9 km/hr
E. can't be determined
BukrsGmat
You can use the formula or the ratio approach.
Formula:
If two objects A and B start simultaneously from opposite points and, after meeting, reach their destinations in ‘a’ and ‘b’ hours respectively (i.e. A takes ‘a hrs’ to travel from the meeting point to his destination and B takes ‘b hrs’ to travel from the meeting point to his destination), then the ratio of their speeds is given by:
\(Sa/Sb = \sqrt{(b/a)} = \sqrt{9/4} = 3/2\)
So the ratio of speeds of first man and second man is 3:2
If the first man cycles at 9 km/hr (which is 3*3), the second will cycle at 2*3 = 6 km/hr
General Discussion
01 Jul 2012, 02:01
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sujit2k7
Hi,
let the speed of second person by x,
and the time taken by them to meet is t,
also, we know that speed of first person is 9km/hr
(BBSR)A------------------------C---------------B(CTC)
supposing they meet at C,
so, distance traveled by first person in t time = distance traveled by second person in 9hrs (=AC)
or 9t=x*9
or x = t
similarly, distance traveled by second person in t time = distance traveled by second person in 4hrs (=CB)
or x*t = 9*4
or \(x^2=36\)
or x=6km/hr
Answer is (B)
Regards,
