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Harley1980
When 120 is divided by positive single-digit integer \(m\) the remainder is positive. When 120 is divided by positive integer \(n\) the remainder is also positive. If \(m<>n\) what is the remainder when 120 is divided by \(|n-m|\)?

1) When 120 divided by integer \(n\) the remainder equal to \(\sqrt{n}\)
2) \(n\) is a single-digit integer



1) From this statement we know that \(n = 9\)
\(120 = 13*9+3\)
And from the task we know that \(120 = m*x + R\) where \(R>0\)
also we know that \(m<>n\) so \(m <> 9\)

When we divide \(120\) on single-digit positive integer only two numbers gives remainder: \(9\) and \(7\) so we can infer that \(m = 7\)
\(|9-7| = 2\) --> \(120/2 = 60\) Remainder is \(0\)
Sufficient

2) When we divide \(120\) on single-digit positive integer only two numbers gives remainder: \(9\) and \(7\) and we know that \(m <> n\) so we can infer that there is two possible variants:
\(m = 7\) and \(n =9\)
or \(m=9\) and \(n = 7\)
\(|9-7| = 2\)
\(|7-9| = 2\)
\(120/2 = 60\) Remainder is \(0\)
Sufficient

Answer is D
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Harley1980

How do you know that for statement 1, that there is no other positive integer that would satisfy the requirement for when 120/n the remainder is sqrt(n). I know that 9 satisfies it, but when your writing the GMAT, and you want to ensure that there is no other possibility, how should one do so? The question stem doesn't state that n has to be a positive single digit.
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Harley1980

How do you know that for statement 1, that there is no other positive integer that would satisfy the requirement for when 120/n the remainder is sqrt(n). I know that 9 satisfies it, but when your writing the GMAT, and you want to ensure that there is no other possibility, how should one do so? The question stem doesn't state that n has to be a positive single digit.


Hi,
the originator has not been online for some time, so let me answer your Q..

1) When 120 divided by integer n the remainder equal to\(\sqrt{n}\)..
as you have written, we cannot straightway jump to answer 9.
but 9 is an answer..

there is one more value of n that I can give you without thinking is 120^2...
the remainder will be 120 here..
so you have two answer possible..
Insuff..

2) n is a single-digit integer
now we know only that n is a single digit ..
Only 7 and 9 leave remainder..
so Suff..

B

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Harley1980
When 120 is divided by positive single-digit integer \(m\) the remainder is positive. When 120 is divided by positive integer \(n\) the remainder is also positive. If \(m<>n\) what is the remainder when 120 is divided by \(|n-m|\)?

1) When 120 divided by integer \(n\) the remainder equal to \(\sqrt{n}\)
2) \(n\) is a single-digit integer

Source: self-made

Hi Harley1980,

The solution given by you along with OA is not correct..

The solution is as follows..

1) When 120 divided by integer \(n\) the remainder equal to \(\sqrt{n}\)
From this statement we know that N is 9 as found by you..
But is 9 the only value possible..

The second value is staring at us right in the Q..
Any value of n >120 will leave a remainder 120..
so 120^2 will also leave a remainder 120..
Second value of n, therefore, is 120^2..
At least two possible values of n: 9 and 120^2..
Insuff

2) \(n\) is a single-digit integer
When we divide \(120\) by single-digit positive integer only two numbers give remainder: \(9\) and \(7\) and we know that \(m \neq n\) so we can infer that there are two possible cases
1) \(m = 7\) and \(n =9\)
2) \(m=9\) and \(n = 7\)

\(|9-7| = 2\)
\(|7-9| = 2\)
\(120/2 = 60\) Remainder is \(0\)
Sufficient

Answer is B

I am changing the OA. Please revert if any query..
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If we look at the original condition, there are 2 variables (m and n) and 1 equation (as 120=2^3*3*5, only m=7 and 9 are possible). In order to match the number of variables to the number of equations we need 1 equation. Since the condition 1) and the condition 2) each has 1 equation, there is high chance that D is the correct answer choice.
In the case of the condition 1), since n=9, 120^2, the answers are not unique and the condition is not sufficient.
In the case of the condition 2), since m=n=7,9 is the only possibility, only |n-m|=2 is possible. Hence, the remainder becomes 0 and the answer becomes unique. The condition, hence is sufficient, and the correct answer choice is B.

- For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
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I really haven't been able to understand how 120^2 is an option at all...If n= 120^2, then we are dividing 120/14400. This no way can ever give the remainder of 120..
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I really haven't been able to understand how 120^2 is an option at all...If n= 120^2, then we are dividing 120/14400. This no way can ever give the remainder of 120..

Hello

When we divide a smaller number by a bigger number, then the smaller number (dividend) itself becomes the remainder, while the quotient becomes 0.

Eg, if we divide 4 by 7, quotient is 0 and remainder is 4 only.
Similarly if we divide 120 by 14400, remainder will be 120 only
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