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Bunuel
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Answer is C as 5 is the length of one side of the square.
A=s^2
5^2=25

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coordiante ; (x1,0) , (x2,1), (x3,4 ), (x4,5)
difference in y coordinate point ; 4-0 ; 4 and 5-1 ; 4
use distance formula to find length of each side ; √4^2+1^2 ; √17
area ; 17

Hi Mr Bunuel,


Not able to comprehend this particular concept. Can you pl eloborate.
Thanking you in anticipation
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Bunuel
A square in the coordinate plane has vertices whose y-coordinates are 0, 1, 4, and 5. What is the area of the square?

(A) 16
(B) 17
(C) 25
(D) 26
(E) 27

All y-coordinates are different therefore it must be a tilted square. The major clue, in this case, is that there are two pairs of points with y-coordinates that have the difference of one: 0, 1 and 4, 5 have the same difference and they make a pair of parallel lines. You can also pair the points with y-coordinates of 0, 4 and 1, 5 and make up the other pair of parallel lines. Therefore the length is sqrt(4^2 + 1^2) = sqrt(17) and the area is 17.
Attachments

tilted square.png
tilted square.png [ 25.99 KiB | Viewed 7231 times ]

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testprepunlimited and satya2029...

thank you very much for this gr8 explanation.
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satya2029
Let's play with Geometry

Another method could be the bigger square PQRS - 4 right triangles i.e. 5*5 - 4*(0.5 * 1 * 4) = 17
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Can someone please explain the solution ?
I am not able to understand how do we get the sqr(1) in sqroot(sqr(4) + sqr(1)) in the above mentioned solutions.
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