Bunuel
In how many ways can you arrange 4 blocks of the same shape and size in a row from left to right after selecting them from one orange, one green, one black, one purple, one white, two red, two yellow and two blue blocks?
(A) 2454
(B) 1950
(C) 990
(D) 975
(E) 960
Solution:We see that there are 8 colors, of which 5 colors have a single block each and 3 colors have two blocks each. Therefore, the 4 blocks can be chosen from the following cases (note: in the calculations below: n in nCr means the number of colors available and r means the number of colors picked. Furthermore, the factor involving factorial means the number of ways one can arrange the 4 blocks once they are chosen. For example, 4! means the number of ways one can arrange the 4 blocks if they are all different colors and 4! / 2! means the number of ways one can arrange the 4 blocks if 2 of them have the same color):
1) All 4 blocks are of different colors:
8C4 x 4! = 70 x 24 = 1680
2) 2 blocks are of the same color and the other 2 are of different colors:
7C2 x 3C1 x 4!/2! = 21 x 3 x 12 = 756
3) 2 blocks are of one color and the other 2 are of the another color:
3C2 x 4!/(2!2!) = 3 x 6 = 18
Therefore, there are a total of 1680 + 756 + 18 = 2454 arrangements.
Answer: A
x 4!/2! = 21 x 3 x 12 = 756 --> Solution obtained is the same no doubt abt that.